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iren2701 [21]
3 years ago
15

Is Heredity nature or nurture?

Physics
2 answers:
Luden [163]3 years ago
8 0
The answer is nature
lubasha [3.4K]3 years ago
8 0

Answer:

Heredity is nature.

Explanation:

Nature is influenced by genetic inheritance and other biological factors. Nurture is taken as the influence of things that you take in after.  Which is like stuff that can be changed such as intelligence.

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Calculate the energy for the transition of an electron from the n = 8 level to the n = 4 level of a hydrogen atom.
34kurt
The netro level 8 and 4 is the hydrogen atom 2. Hope u enjoy your grade
5 0
4 years ago
What is the work function of cadmium metal if light with = 9.85×1014hz is necessary to eject electrons?
Alika [10]

We use the Planck’s formula:

E = hv

where,

E = energy, h = planck’s constant = 6.6x10^-34 J s, v = frequency in Hz (Hz = 1 / s)

 

Subsituting the values to find for E:

E = (6.6×10^-34 J s) * 9.85×10^14 / s

E = 6.5x10^-19 J

3 0
3 years ago
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
Nesterboy [21]

Answer:

Compression distance: d \approx 0.102\,m

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy (K), in joules, at the expense of elastic potential energy (U), in joules, and overcoming work losses due to friction (W_{l}), in joules:

K + W_{l} = U (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2} (2)

Where:

m - Mass of the block, in kilograms.

v - Final velocity of the block, in meters per second.

\mu - KInetic coefficient of friction, no unit.

g - Gravitational acceleration, in meters per square second.

s - Width of the rough patch, in meters.

k - Spring constant, in newtons per meter.

d - Compression distance, in meters.

If we know that m = 1.2\,kg, v = 2.3\,\frac{m}{s}, \mu = 0.44, g = 9.807\,\frac{m}{s^{2}}, s = 0.05\,m and k = 730\,\frac{N}{m}, then the compression distance of the spring is:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2}

m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}

d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }

d \approx 0.102\,m

4 0
3 years ago
Connecting many devices in a single socket does not affect the flow of current in a
eimsori [14]

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u><em> </em><em>F</em><em>a</em><em>l</em><em>s</em><em>e</em>

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7 0
3 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
PilotLPTM [1.2K]

Answer:

859.07 N

Explanation:

u = Initial velocity = 1.9 m/s

v = Final velocity

s = Displacement = 0.165 m

a = Acceleration

m = Mass = 890 kg

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-1.9^2}{2\times 0.165}\\\Rightarrow a=-10.93\ m/s^2

Force

F=ma\\\Rightarrow F=870\times -10.93\\\Rightarrow F=859.07\ N

The magnitude of the average force on the bumper is 859.07 N

4 0
3 years ago
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