Answer:
Options 1 and 5 are correct
Explanation:
Magnetic field lines can never cross, the field is unique at any point in space. Magnetic field lines are continuous, forming closed loops without beginning or end. They go from the north pole to the south pole.
Magnetic field lines form closed loops but do not intersect.
Electric field lines originate at the positive charges and terminate at the negative charges. They move in a straight line and are parallel. Electric field lines neither form closed loops nor intersect.
Since, magnetic field lines form closed loops and move from North to South pole, they come out of north poles outside the magnet and into north poles inside the magnet, they also go into south poles outside the magnet and out of south poles inside the magnet.
Answer:
Final velocity of the block = 2.40 m/s east.
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum
Mass of bullet = 0.0140 kg
Consider east as positive.
Initial velocity of bullet = 205 m/s
Mass of Block = 1.8 kg
Initial velocity of block = 0 m/s
Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s
Final velocity of bullet = -103 m/s
We need to find final velocity of the block( u )
Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u
We have
2.87 = -1.442 + 1.8 u
u = 2.40 m/s
Final velocity of the block = 2.40 m/s east.
Answer:
4 A
Explanation:
V = IR, where V=voltage, I=current, R=resistance. This is Ohm's Law. (remember that for units V = volts, Ω = ohms, A = amperes.)
V = IR
12 V = I * 3 Ω
12/3 = I
<u>I = 4 A</u>
Answer:
4.4721m
Explanation:
#Use Pythagorean theorem to find the distance between the two speakers:
There are antinodes 1/4,1/2 and 3/4 of the distance between speakers.
The greatest antinode is 3/4-1/4=1/2
#Distance between consecutive antinodes is:
Hence, the maximum possible wavelength of the sound waves is 4.4721m
Answer:
d = 61.75 m
Explanation:
Given that,
A ball droped from a building.
We need to find how fast is it traveling after falling 3.55 s.
As it is dropped, its initial velocity is equal to 0.
Let d is the distance it covers after falling 3.55 s.
We can use second equation of motion to find d.
Here, u = 0 and a =g
So, it will cover 61.75 m after falling 3.55 seconds.
