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3 years ago

Gravity on Earth is 9.8 m/s2, and gravity on Mars is 3.7 m/s2.

Physics

2 answers:

antiseptic1488 [7]3 years ago

8 0

W = mg

Weight on Earth = 50 x 9.8
= 490 N

Weight on Mars = 50 x 3.7
= 185 N

maria [59]3 years ago

6 0

Answer

Weight of the Jaden on earth is 490 N.

Weight of the Jaden on mars is 185 N.

Explanation:

Formula

w = mg

Where w is the weight of an object , m is the mass of an object and g is acceleration of gravity .

Case First

Gravity on Earth is 9.8 m/s² .

Jaden’s mass is 50 kilograms.

g = 9.8 m /s²

m = 50

Put the values in the formula

Thus

w = 50 × 9.8

= 490 kg m /s²

(As N = kg m/ s²)

= 490 N

Therefore the weight of the Jaden on earth is 490 N.

Case Second

Gravity on Mars is 3.7 m/s².

Jaden’s mass is 50 kilograms.

m = 50 kg

g = 3.7 m/s²

Putting the values in the formula

w = 50 × 3.7

= 185 kg m/s²

(As N = kg m/ s²)

= 185 N

Therefore the weight of the Jaden on mars is 185 N.

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3 years ago

A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.

galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s$

$v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s$

Time taken to reach 1180 m is 11.29 seconds

$v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s$

Time the rocket will keep going up after the engines shut off is 13.06 seconds.

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m$

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s$