Na, C, and O so the answer is c. 3
Answer is: 8568.71 of baking soda.
Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.
V(H₂SO₄) = 17 L; volume of the sulfuric acid.
c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.
n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).
n(H₂SO₄) = 17 L · 3 mol/L.
n(H₂SO₄) = 51 mol; amount of sulfuric acid.
From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.
n(NaHCO₃) = 2 · 51 mol.
n(NaHCO₃) = 102 mol, amount of baking soda.
m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).
m(NaHCO₃) = 102 mol · 84.007 g/mol.
m(NaHCO₃) = 8568.714 g; mass of baking soda.
Answer:
![\boxed{\text{4.00 mol}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B4.00%20mol%7D%7D)
Explanation:
Use Avogadro’s number to convert formula units of RbNO₃ to moles of RbNO₃.
1 mol RbNO₃ ≡ 6.022 × 10²³ formula units RbNO₃
Moles of RbNO₃ = 2.41 ×1 0²⁴ ×
= 4.00 mol RbNO₃
There are
of RbNO₃ in 2.41 × 10²⁴ formula units.