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scoundrel [369]
4 years ago
8

Start a conclusion based on the data from this experiment

Chemistry
1 answer:
Mandarinka [93]4 years ago
4 0
The number of chirps increases in relation to temperature.
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3. If a cation replaces an anion, the compound would have 2 positive charges. Why would this never happen
Jet001 [13]

A cation will not replace an anion in a compound because the two positively-charged ions will repel each other.

<h3>Ions</h3>

Ions are atoms or group of atoms possessing an electrical charge.

  • Positively-charged ions are known as cations.
  • Negatively-charged ions are known as anions.

<h3>Ionic compounds</h3>

Ionic compounds are compounds which are composed of oppositely charged ions held together by strong electrostatic forces of attraction between the oppositely charged ions.

  • From law of electrostatics, like charges repel and unlike charges attract.

If a cation replaces an anion, the compound would have two l positive charges which will repel each other.

Therefore, a cation will not replace an anion in a compound because the two positively-charged ions will repel each other.

Learn more about ions and electrostatics at: brainly.com/question/13690700

3 0
3 years ago
Which is the correct Lewis structure for acetylene (C2H2)?
Yuki888 [10]
Rnxrxejxfrx rn coo dmre teeter eert deep xhjhjyf. Right on here we have no problem finding the one r
6 0
3 years ago
Please help quick im on a test and i only got an few mins left
Art [367]

Answer:

hey

Explanation:

7 0
3 years ago
Read 2 more answers
The reaction between solid white phosphorous and oxygen produces solid tetraphosphorous decaoxide (P4O10). The balanced
iren [92.7K]
C I think :) maybe hope this helps
6 0
3 years ago
consider an exceptionally weak acid, HA, with Ka= 1 x 10-20. you make 0.1M solution of the salt NA. what is the pH.
iogann1982 [59]

Answer:

pH=10.5

Explanation:

Hello,

In this case, the dissociation of the given weak acid is:

HA\rightleftharpoons H^++A^-

Therefore, the law of mass action for it turns out:

Ka=\frac{[H^+][A^-]}{[HA]}

That in terms of the change x due to the reaction extent is:

1x10^{-23}=\frac{x*x}{0.1-x}

Thus, by solving with the quadratic equation or solver, we obtain:

x=31.6x10^{-12}M

Which clearly matches with the hydrogen concentration in the solution, therefore, the pH is:

pH=-log(-31.6x10^{-12})\\pH=10.5

Regards.

5 0
3 years ago
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