If the object is moving in a straight line at a constant speed, then that's
the definition of zero acceleration. It can only happen when the sum of
all forces (the 'net' force) on the object is zero.
And it doesn't matter what the object's mass is. That argument is true
for specks of dust, battleships, rocks, stars, rock-stars, planets, and
everything in between.
Answer:The place to go for the answer to such an easy question is the SI Brochure, the document which defines the SI and all its units.
Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s
<span>x component = sine ( 32 ° ) * 20.583 = 10.91 m/s
hope this helps :)
</span>
Answer:
Induced current, I = 18.88 A
Explanation:
It is given that,
Number of turns, N = 78
Radius of the circular coil, r = 34 cm = 0.34 m
Magnetic field changes from 2.4 T to 0.4 T in 2 s.
Resistance of the coil, R = 1.5 ohms
We need to find the magnitude of the induced current in the coil. The induced emf is given by :
![\epsilon=-N\dfrac{d\phi}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D-N%5Cdfrac%7Bd%5Cphi%7D%7Bdt%7D)
Where
is the rate of change of magnetic flux,
And ![\phi=BA](https://tex.z-dn.net/?f=%5Cphi%3DBA)
![\epsilon=-NA\dfrac{dB}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D-NA%5Cdfrac%7BdB%7D%7Bdt%7D)
![\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}](https://tex.z-dn.net/?f=%5Cepsilon%3D-78%5Ctimes%20%5Cpi%20%280.34%29%5E2%5Cdfrac%7B%280.4-2.4%29%7D%7B2%7D)
![\epsilon=28.32\ V](https://tex.z-dn.net/?f=%5Cepsilon%3D28.32%5C%20V)
Using Ohm's law, ![\epsilon=I\times R](https://tex.z-dn.net/?f=%5Cepsilon%3DI%5Ctimes%20R)
Induced current, ![I=\dfrac{\epsilon}{R}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B%5Cepsilon%7D%7BR%7D)
![I=\dfrac{28.32}{1.5}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B28.32%7D%7B1.5%7D)
I = 18.88 A
So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.