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antiseptic1488 [7]
3 years ago
5

Explain what relative weight is and why it is important to the calculation of atomic mass.

Physics
1 answer:
Colt1911 [192]3 years ago
7 0
Relative weight- weight that is relevant, and it is important to calculate atomic mass because that's the answer
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The path of electric current is known as___
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Answer:

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Why heat capacity for polymer higher than metal?
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4 0
4 years ago
A 0.23-f capacitor is desired. What area must the plates have if they are to be separated by a 3.8-mm air gap?
tia_tia [17]

The area of the plates must have is(A)= 9.91×10⁷ m²

<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>

To calculate the the value of a area of the plates of a capacitor, we are using the formula,

C=\frac{\epsilon_0 A}{d}

Or, A= \frac{C\times d}{\epsilon_0}

Here we are given,

C= The desired capacitance of a capacitor.

= 0.23F

d=distance of separation between the plates.

=3.8mm= 0.0038m.

\epsilon_0= permittivity of the vacuum.  

=8.854×10⁻¹²F/m

We have to calculate the area of the plates must have = A m².

Now we put the known values in the above equation, we can get

A= \frac{C\times d}{\epsilon_0}

Or, A=\frac{0.23\times 0.0038}{8.854\times 10^{-12}}

Or, A= 9.91×10⁷ m²

From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²

Learn more about Capacitor:

brainly.com/question/13578522

#SPJ4

5 0
2 years ago
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