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PilotLPTM [1.2K]
3 years ago
15

What is the answer to this problem?

Chemistry
1 answer:
julsineya [31]3 years ago
3 0

Answer:

Ask your teacher

Explanation:

(use formula online)

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Calculate (a) the number of moles of hydrogen required to react with 0.0969 moles of nitrogen, and (b) the number of moles of am
Bumek [7]

Answer:

The answer to your question is:

Explanation:

Data

moles H=?

moles of N = 0.0969

moles of NH₃=?

                            N₂ (g)  + 3 H₂ (g)  ⇒   2NH₃ (g)

Process

1.- Set a rule of three to calculate the moles of hydrogen

                         1 mol of nitrogen  -------------   3 moles of hydrogen

                         0.0969 moles of N ----------     x

                         x = (0.0969 x 3) / 1

                         x = 0.2907 moles of hydrogen          

2.- Set a rule of three to calculate the moles of ammonia

                        1 mol of nitrogen --------------  2 moles of ammonia

                        0.0969 mol of N --------------   x

                        x = (0.0969 x 2) / 1

                        x = 0.1938 moles of ammonia                

5 0
3 years ago
What's the word of a theory that states that earths crust and upper mantle are broken into sections which move around on a speci
zaharov [31]
The Plate Tectonic Theory
5 0
3 years ago
Read 2 more answers
Water droplets forming on the inside of a cold windshield is an example of
8_murik_8 [283]
Condensation I think.
4 0
3 years ago
Read 2 more answers
Does the hydrogen molecule obey the octet rule?
Alja [10]

Explanation:

Hydrogen does not obey the octet rule. Boron does not always

obey the octet rule and in fact forms Lewis acids such as BF3 which

only has 6 electrons.

6 0
3 years ago
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
max2010maxim [7]

Answer:

The answer to your question is: Initial temperature of copper = 67.1°C

Explanation:

Data

mass Copper = 248 g

volume Water = 390 ml

T1 water = 22.6°C

T2           = 39.9°C

T1 copper = ?

Specific heat water = 1 cal/g°C

Specific heat copper = 0.092 cal/g°C

Formula       copper             water

Heat is negative for copper because it releases heat

                  - mCp(T2 - T1) = mCp(T2 - T1)                  

                  - (248)(39.9 - T1) = 390 (1)((39.9 - 22.6)           Substitution

                 -9895.2 + 248T1 = 390(17.3)                             Simplification

                 -9895.2 + 248T1 = 6747

                 248 T1 = 6747 + 9895.2

                 248 T1 = 16642.2

                 T1 = 16642.2 / 248

                 T1 = 67.1 °C                                                         Result

6 0
3 years ago
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