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Mashutka [201]
3 years ago
9

4C,H,O2N + 2H2O → 3CH4 + 5CO2 + 4NH3

Chemistry
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

the equation is not balanced

Explanation:

but the one in the picture is balanced

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The half-life of a radioactive isotope is the amount of time it takes for a quantity of that isotope to decay to one half of its
Sedaia [141]

Radio active decay reactions follow first order rate kinetics.

a) The half life and decay constant for radio active decay reactions are related by the equation:

t_{\frac{1}{2}} =\frac{ln 2}{k}

t_{\frac{1}{2}} = \frac{0.693}{k}

Where k is the decay constant

b) Finding out the decay constant for the decay of C-14 isotope:

Decay constant (k) = \frac{0.693}{t_{\frac{1}{2}}}

k = \frac{0.693}{5230 years}

k = 1.325 * 10^{-4} yr^{-1}

c) Finding the age of the sample :

35 % of the radiocarbon is present currently.

The first order rate equation is,

[A] = [A_{0}]e^{-kt}

\frac{[A]}{[A_{0}]} = e^{-kt}

\frac{35}{100} = e^{-(1.325 *10^{-4})t}

ln(0.35) = -(1.325 *10^{-4})(t)

t = 7923 years

Therefore, age of the sample is 7923 years.

3 0
3 years ago
Suppose that in an ionic compound, "m" represents a metal that could form more than one type of ion. in the formula mf2 , the ch
geniusboy [140]
F (Fluorine) is in column (group/family) VIIA, or the "halogens". When you see the halogens (Fluorine, Chlorine, Bromine, and Iodine) in combination with a metal, each halogen atom present will carry a -1 charge. We can see that the atom has no charge, so the metal must cancel out the negative charges brought by the two fluorine atoms.
(Charge on m) + 2*(charge on fluorine) = 0
(Charge on m) + 2*(-1) = 0
(Charge on m) - 2 = 0
Charge on m ion = +2
3 0
3 years ago
People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m
Llana [10]

Answer:

V_{HCl}=0.208L=208mL

Explanation:

Hello,

In this case, since the chemical reaction is:

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

n_{HCl}=2*n_{Mg(OH)_2}

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g}  =0.00858mol

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M

Then, since the concentration and the volume define the moles, we can write:

[HCl]*V_{HCl}=2*n_{Mg(OH)_2}

Therefore, the neutralized volume turns out:

V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL

Best regards.

3 0
3 years ago
Can anyone pls help? (fill in the blank)
masya89 [10]

Answer:

reactivity:very reactive,less reactive

density:float in water,sink in water

melting and boiling point:low,high

colour of salts: colourless,often coloured

3 0
3 years ago
A 7th grade science class placed three large grade A eggs into beakers and recorded the mass. They then filled one beaker with v
lisov135 [29]
Independent- The vinegar,corn syrup, distilled water
Dependent- The mass of the egg
Constant- the egg and the beaker 


3 0
3 years ago
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