1. Decreases by 4. (B)
2. The atomic number changes. (B)
3. 56/26 Fe. (C)
4. Potassium-40;t1/2=25 days. (B)
5. Takes place in the upper atmosphere. (A)
Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
The required net ionic equation is; 2H^+(aq) + 2OH^-(aq)-----> 2H2O(l)
The molecular reaction equation is;
H2SeO3(aq) + 2KOH(aq) -----> K2SeO3(aq) + 2H2O(l)
The complete ionic equation is;
2H^+(aq) + SeO3^2-(aq) + 2K^+(aq) + 2OH^-(aq)-----> 2K^+(aq) + SeO3^2-(aq) + 2H2O(l)
Net ionic equation;
2H^+(aq) + 2OH^-(aq)-----> 2H2O(l)
We can clearly see that this is a neutralization reaction hence water is the product of the net ionic equation.
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