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vodomira [7]
2 years ago
15

Using a 300 MHz NMR instrument:

Chemistry
1 answer:
Softa [21]2 years ago
6 0

Answer:

a. 750Hz, b. 4.0ppm, c. 600Hz

Explanation:

The Downfield Shift (Hz) is given by the formula

Downfield Shift (Hz) = Chemical Shift (ppm) x Spectrometer Frequency (Hz)

Using the above formula we can solve all three parts easily

a. fspec = 300 MHz, Chem. Shift = 2.5ppm, 1MHz = 10⁶ Hz, 1ppm (parts per million) = 10⁻⁶

Downfield Shift (Hz) = 2.5ppm x 300MHz x (1Hz/10⁶MHz) x (10⁻⁶/1ppm)

Downfield Shift = 750 Hz

The signal is at 750Hz Downfield from TMS

b. Downfield Shift = 1200 Hz, Chemical Shift = ?

Chemical Shift = Downfield shift/Spectrometer Frequency

Chemical Shift = (1200Hz/300MHz) x (1ppm/10⁻⁶) = 4.0 ppm

The signal comes at 4.0 ppm

c. Separation of 2ppm, Downfield Shift = ?

Downfield Shift (Hz) = 2(ppm) x 300 (MHz) x (1Hz/10⁶MHz) x (10⁻⁶/1ppm) = 600 Hz

The two peaks are separated by 600Hz

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Answer:

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Explanation:

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X= 5.82×10^23/ 6.02×10^23

X = 0.97 moles of tungsten

6 0
2 years ago
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Novay_Z [31]

Answer:

<h2>4.03 × 10²³ atoms</h2>

Explanation:

The number of S atoms can be found by using the formula

<h3>N = n × L</h3>

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From the question we have

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We have the final answer as

<h3>4.03 × 10²³ atoms</h3>

Hope this helps you

7 0
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alexandr402 [8]
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3 years ago
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