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vodomira [7]
3 years ago
15

Using a 300 MHz NMR instrument:

Chemistry
1 answer:
Softa [21]3 years ago
6 0

Answer:

a. 750Hz, b. 4.0ppm, c. 600Hz

Explanation:

The Downfield Shift (Hz) is given by the formula

Downfield Shift (Hz) = Chemical Shift (ppm) x Spectrometer Frequency (Hz)

Using the above formula we can solve all three parts easily

a. fspec = 300 MHz, Chem. Shift = 2.5ppm, 1MHz = 10⁶ Hz, 1ppm (parts per million) = 10⁻⁶

Downfield Shift (Hz) = 2.5ppm x 300MHz x (1Hz/10⁶MHz) x (10⁻⁶/1ppm)

Downfield Shift = 750 Hz

The signal is at 750Hz Downfield from TMS

b. Downfield Shift = 1200 Hz, Chemical Shift = ?

Chemical Shift = Downfield shift/Spectrometer Frequency

Chemical Shift = (1200Hz/300MHz) x (1ppm/10⁻⁶) = 4.0 ppm

The signal comes at 4.0 ppm

c. Separation of 2ppm, Downfield Shift = ?

Downfield Shift (Hz) = 2(ppm) x 300 (MHz) x (1Hz/10⁶MHz) x (10⁻⁶/1ppm) = 600 Hz

The two peaks are separated by 600Hz

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3.0 M HI Unknown NaOH initial burette reading 0.2 ml 0.7 ml final burette reading 47.6 ml 37.5 ml What is the concentration of t
stich3 [128]

This is a neutralization, which means we are mixing a base with an acid until the mixture becomes neutral. We add more HI to the NaOH until the number of acid equivalents is equal to the number of base equivalents. We can calculate the acid equivalents using normality and volume, and the same with base equivalents.

A = acid equivalents = normality*volume (in the acid solution)

B = base equivalents = normality*volumen (in the base solution)

A = B

NA*VA = NB*VB

HI is an acid which releases only 1 acid equivalent per molecule, so its molarity is equal to its normality.

NaOH is a base which releases only 1 base equivalent per formula unit, so its molarity is equal to its normality.

MA*VA = MB*VB

We’re trying to find out NaOH molarity, which is equal to the NaOH normality.

MB = MA*VA/VB

DATA:

MA = 3.0 M

<span>The volumen of HI used can be calculated by subtracting the final volume of the burette to its initial volume (the final volume is smaller, as we have taken some volume away)</span>

VA = V0-Vf = 0.7 ml - 0.2 ml = 0.5 ml

VB = V0-Vf = 47.6 ml - 37.5 ml = 10.1 ml

MB = 3.0M*0.5M/10.1M = 0.149 M

6 0
3 years ago
How many molecules of CO2 at standard temperature and pressure in 5.4 moles of CO2
olganol [36]

Answer:

3.25×10²⁴ molecules.

Explanation:

From the question given above, the following data were obtained:

Number of mole of CO₂ = 5.4 moles

Number of molecules of CO₂ =?

The number of molecules of CO₂ in 5.4 moles can be obtained as follow:

From Avogadro's hypothesis,

1 mole of CO₂ = 6.02×10²³ molecules

Therefore,

5.4 moles of CO₂ = 5.4 × 6.02×10²³

5.4 moles of CO₂ = 3.25×10²⁴ molecules

Thus, 5.4 moles of CO₂ contains 3.25×10²⁴ molecules.

8 0
3 years ago
Empirical formula for 6. 63.52% Fe, 36.48% S
emmasim [6.3K]
The empirical formula for this would be FeS
8 0
3 years ago
There is 35 mg of sodium in a can of Coke. You determine it to be 28 mg. What is your percent error?
natali 33 [55]

Answer:

The answer is

<h2>20 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 35 mg

error = 35 - 28 = 7

The percentage error is

P(\%) =  \frac{7}{35}  \times 100 \\  =  \frac{1}{5}  \times 100 \\  =  20

We have the final answer as

<h3>20 %</h3>

Hope this helps you

8 0
3 years ago
Read 2 more answers
Reason why chemistry is studied
mina [271]

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Explanation:

3 0
3 years ago
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