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3 years ago

Using a 300 MHz NMR instrument:

Chemistry

1 answer:

Softa [21]3 years ago

6 0

Answer:

a. 750Hz, b. 4.0ppm, c. 600Hz

Explanation:

The Downfield Shift (Hz) is given by the formula

Downfield Shift (Hz) = Chemical Shift (ppm) x Spectrometer Frequency (Hz)

Using the above formula we can solve all three parts easily

a. fspec = 300 MHz, Chem. Shift = 2.5ppm, 1MHz = 10⁶ Hz, 1ppm (parts per million) = 10⁻⁶

Downfield Shift (Hz) = 2.5ppm x 300MHz x (1Hz/10⁶MHz) x (10⁻⁶/1ppm)

Downfield Shift = 750 Hz

The signal is at 750Hz Downfield from TMS

b. Downfield Shift = 1200 Hz, Chemical Shift = ?

Chemical Shift = Downfield shift/Spectrometer Frequency

Chemical Shift = (1200Hz/300MHz) x (1ppm/10⁻⁶) = 4.0 ppm

The signal comes at 4.0 ppm

c. Separation of 2ppm, Downfield Shift = ?

Downfield Shift (Hz) = 2(ppm) x 300 (MHz) x (1Hz/10⁶MHz) x (10⁻⁶/1ppm) = 600 Hz

The two peaks are separated by 600Hz

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Fish need about 5 ppm oxygen dissolved in water to survive. Will water with 5 mg oxygen per

Lelechka [254]

5mg in liter is 5 ppm

Explanation: 1 ppm is one part per million.

1 ppm is 1 mg is one part of million from 1 kg = 1000 000 mg

1 litre water is 1. Kg.

3 0

3 years ago

Can you please help me and can you show your work please

natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

$1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O$

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

$1.2mol*\frac{40.00g}{1mol} =41.2g$

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

$45g*\frac{1mol}{180.15g}=0.25g$

4. Here, since the molar mass of ammonia is 17.03 g/mol:

$20mol*\frac{17.03g}{1mol}=340.6g$

5. Here, since the molar mass of SO2 is 64.06 g/mol:

$48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules$

Best regards!

5 0

3 years ago

Compound X has a molar mass of 266.64 g/mol and the following composition: aluminum 20.24% chlorine 79.76% Write the molecular f

N76 [4]

Answer:

Explanation:

Assume we have 100g of this substance. That means we would have 20.24g of Cl and 79.76g of Al. Now we can find how many moles of each we have:

$\frac{79.76 \:g}{35.45 \: g/mol}$ = 2.25 mol of chlorine

$\frac{20.24 \: g}{26.98 \: g/mol}$ = 0.750 mol of Al.

To form a integer ratio, do 2.25/0.75 = 2.99999 ~= 3.

So the ratio is essentially Al : Cl => 1 : 3. To the compound is possibly $AlCl_3$ .

However, it says it has a molar mass of 266.64 g/mol, and since AlCl3 has a molar mass of 133.32, it must be $Al_2Cl_6$ .

Actually this molecule isn't exactly AlCl3 (which is ionic). Al2Cl6 forms a banana bond where Cl acts as a hapto-2 ligand. But that's a bit advanced. All you need to know is X = Al2Cl6

5 0

2 years ago

PLEASE HELP ASAP!!!!!!!!!!!!! I dont understand this stuff at all.........

serious [3.7K]

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4 0

3 years ago

A vector is represented as a ____

monitta

I hope this helped you have a good day

3 0

2 years ago