Answer:
43.13Kg of melamine
Explanation:
The problem gives you the mass of urea and two balanced equations:
First we need to calculate the number of moles of urea that are used in the reaction, so:
molar mass of urea =
The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:
161.2Kg of urea2684 moles of urea
Now from the stoichiometry you have:
2684 moles of urea = 447 moles of melamine
The molar mass of the melamine is so we have:
= 5637.64 g of melamine
Converting that mass of melamine to Kg:
5637.64 g of melamine * = 56.38 Kg of melamine, that is the theoretical yield of melamine.
Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:
%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)
Actual yield of melamine = = 43.13Kg of melamine
