Question

Melamine (C3N3(NH2)3) is a component of many adhesives and resins and is manufactured in a two-step

Answer 1

Answer:

43.13Kg of melamine

Explanation:

The problem gives you the mass of urea and two balanced equations:

First we need to calculate the number of moles of urea that are used in the reaction, so:

molar mass of urea =

The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:

161.2Kg of urea2684 moles of urea

Now from the stoichiometry you have:

2684 moles of urea = 447 moles of melamine

The molar mass of the melamine is  so we have:

= 5637.64 g of melamine

Converting that mass of melamine to Kg:

5637.64 g of melamine * = 56.38 Kg of melamine, that is the theoretical yield of melamine.

Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:

%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)

Actual yield of melamine =  = 43.13Kg of melamine