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2 years ago

A 0.25 kg book falls off a 2 m shelf on to a 0.5 m chair. What was the change in GPE?

Physics

1 answer:

Snowcat [4.5K]2 years ago

6 0

The equation of GPE is mgH, where m is mass, g is gravitational acceleration, and H is the height.

If we're solving for the change in GPE, then:

∆ $U_{g}$ = mg∆H

Input our given values for m and g:

∆ $U_{g}$ = 0.25 * 9.80 * ∆H

The book falls from 2 meters high to 0.5 meters high, so:

∆ $U_{g}$ = 0.25 * 9.80 * (2.0 - 0.5)

∆ $U_{g}$ = 0.25 * 9.80 * 1.5

∆ $U_{g}$ = 3.675 (J)

Adjust for significant figures:

∆ $U_{g}$ = 3.7 (J)

The change in gravitational potential energy was 3.7 (J)

If you have any questions on anything I did to get to the answer, just ask!

- breezyツ

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3 years ago

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Lemur [1.5K]

Answer:

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The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

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