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Brut [27]
4 years ago
9

An 100 V/m electric field is directed along the x axis. If the potential at the origin is 300 V, what is potential at the point

( -2m, 0) point

Physics
2 answers:
Ede4ka [16]4 years ago
8 0

Answer:

<em>100 V</em>

<em></em>

Explanation:

Electric field E = 100 V/m

Potential at the origin = 300 V

Potential at point (-2m, 0) i.e 2 m behind the origin = ?

From the equation ΔV = EΔd,

ΔV = V_{0} - V_{x}

where V_{0} is the potential at origin,

and V_{x} is the potential at point (-2, 0)

E = electric field

Δd = 0 - (-2) = 2 m

V_{0} - V_{x} = 300 - x

equating, we have

 300 - x = 100 x 2

300 - x = 200

x = <em>100 V</em>

Alex_Xolod [135]4 years ago
6 0

Answer:

200volts

Explanation:

Pls see attached file

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With the addition of vectors we can find that the correct answer is:

   C)   Q> P > R =  S > T

The addition of vectors must be done taking into account that they have modulus and direction. The analytical method is one of the easiest methods, the method to do it is:

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In this exercise indicate that the modulus of all vectors is the same, suppose that the value of the modulus is A.

We fix a Cartesian coordinate system with the horizontal x axis and the vertical y axis, we can see that we do not need to perform any decomposition, so we perform the algebraic sums

Diagram P

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The modulus of the resulting vector can be found with the Pythagorean Theorem

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          P = 2 √2  A

         

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y-axis  

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       Q = \sqrt{x^2+y^2}

       Q =\sqrt{9A^2 + A^2 }  

       Q = \sqrt{10} \ A

       

Diagram R

x- axis

       x = 0

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Resulting

       R =\sqrt{4A^2 + 0}  

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Diagram S

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Diagram T

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We order the diagram from highest to lowest

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When reviewing the different answers, the correct one is:

   C.  Q> P> R = S> T

Learn more about adding vectors here:

brainly.com/question/14748235

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