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3 years ago

prepara un escrito en el que resumas las ideas principales sobre la evolución de los modelos atómicos

Physics

1 answer:

Dvinal [7]3 years ago

3 0

Mexico Mexico language to is the answer to the question

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A child walks due east on the deck of a ship at 2 miles per hour. the ship is moving north at a speed of 18 miles per hour. find

garik1379 [7]

Refer to the figure shown below.

The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.

The magnitude of the child's velocity is
v = √(2² + 18²) = 18.11 mph

The direction of the child's speed is
θ = tan⁻¹ (18/2) = tan⁻¹ 9 = 83.7° north of east or counterclockwise from the eastern direction.

Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.

8 0

3 years ago

How long would it take for a sound impulse to travel through a copper Rod 20km

Nana76 [90]

Not sure.can you give me a clue?

8 0

3 years ago

Compare and contrast electric potential energy and electric potential difference? Explain.

forsale [732]

Answer:

Electric Potential Energy:

The energy that is needed to move a charge against an electric firld is called Electric Potential Energy

Electric Potential Difference:

The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.

Relation:

Relation between Electric potential and electrical potential energy is given by

$\delta V=\frac{PE}{q}$

Here PE represents Electric potential energy

and $\delta V$ is Electric potential difference

it means electric potential difference is the difference in electric potential energy divided by the charge.

6 0

3 years ago

Which is not a device for reproducing sound?

Alona [7]

Phonograph. Hope that helps

7 0

3 years ago

A bird lands on a bare copper wire carrying a current of 51

nirvana33 [79]

The resistance of the piece of wire is
$R= \frac{\rho L}{A}$
where
$\rho = 1.68 \cdot 10^{-8}\Omega m$ is the resistivity of the copper
$L=5.1 cm=0.051 m$ is the length of the piece of wire
$A=0.13 cm^2 = 0.13 \cdot 10^{-4} m^2$ is the cross sectional area of the wire
By substituting these values, we find the value of R:
$R= \frac{\rho L}{A}=6.6 \cdot 10^{-5} \Omega$

Then, by using Ohm's law, we find the potential difference between the two points of the wire:
$V=IR=(51 A)(6.6 \cdot 10^{-5} \Omega )=3.4 \cdot 10^{-3} V$

7 0

3 years ago