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pav-90 [236]
3 years ago
7

What is true about resistance? Check all that apply. A. It is the excess accumulation of electric charge B. It is measured in oh

ms. C. It is the opposition of movement of electric charge. D. It is measured in amps. E. It is related to voltage and current by Ohm's Law.
Physics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

B, C and E

Explanation:

The unit of resistance in the international system is the Ohm, the equation that describes the resistance is:

R=p\frac{l}{S} \\

Where (l) is for lenght of the wire, (S) is the area and (p) its the constant associated to the conductor.

It's related by the Ohm's Law:

R=\frac{V}{I}

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Answer:

  • See the graph attached with the vectors.

Explanation:

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The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.

Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.

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3 years ago
A copper cable needs to carry a current of 160 A with a power loss of only 2.0 W/m. What is the required radius of the copper ca
lesantik [10]

Answer:

The radius of the cable is 0.0083 m or 8.3 mm.

Explanation:

The resistance of copper cable of 1 meter length will be given by

R_{cable} = \frac{\rho \times l}{a}    ....     (i)

where the resistivity of copper is \rho = 1.7 \times 10^{-8} \Omega.m , and l is the length of the wire which is considered to be 1m, and a is the cross sectional area of the wire in m^{2}.

From the formula of power we know that, P = I^2 R    ....    (ii)

Therefore 2 W/m  = (160)^2 \times R     ....     (iii)  

where  the resistance,R, actually means the resistance of the cable per meter.

Therefore R ( resistance of cable per meter)

= \frac{2}{160^2}  = 7.812 \times 10^{-5} ohms / meter.       ....    (iv)

Therefore from (i)

7.812 \times 10^{-5} = \frac{1.7 \times 10^{-8} \times 1}{a}  = \frac{1.7 \times 10^{-8} \times 1}{\pi r^{2} }       .....     (v)

where cross sectional area of the cable, a  = \pi r^2,

where r is the radius of the cable, and length of cable,l = 1m.

Therefore r  = \sqrt{\frac{ 1.7 \times 10^{-8}}{\pi \times 7.812 \times 10^{-5} } }  =  0.0083m = 8.3 mm

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3 years ago
The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance
belka [17]

The gravitational force between the spheres is

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Is there proof of the existence of God and Satan?If so what proof?
ivolga24 [154]
Religiously it has been proved that God exist and even satan exist
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but my advise for you is to ask God to show you if He truly exist

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3 years ago
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