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lara31 [8.8K]
4 years ago
5

If the distance between two objects is increased,the gravitational attraction between them will.....?

Physics
2 answers:
Archy [21]4 years ago
5 0
Attraction will decrease
tia_tia [17]4 years ago
4 0

The attraction will decrease. Hope I helped :)

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You and your friends are driving down the road. Your car breaks down. You have to use a 1,210 N force to push the car 201 m to t
Katyanochek1 [597]

Answer:

2.43\cdot 10^5 J

Explanation:

Since the force applied is parallel to the displacement of the car, the work done on the car is simply given by:

W=Fd

where

F = 1210 N is the force applied on the car

d = 201 m is the displacement of the car

Substituting numbers into the equation, we find:

W=(1210 N)(201 m)=2.43\cdot 10^5 J

5 0
4 years ago
A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.
tamaranim1 [39]

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

  • mass of the car, m = 1400 kg
  • Initial velocity of the car, u = 25 m/s
  • coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

5 0
3 years ago
Which of the following best describes applying a force over a period of time?
Mazyrski [523]
Impulse
it’s the only one that makes sense energy is just light and power almost the same thing
7 0
3 years ago
A 12 v automobile battery is connected to an electric starter motor. the current through the motor is 206
vampirchik [111]
Power = (voltage) x (current). The motor consumes (12)x(206)=2,472 watts. Some of it is dissipated as heat, but most of it is used to do useful work by turning the engine over to make it start.
5 0
3 years ago
An object is dropped from a​ tower, 400 ft above the ground. The​ object's height above ground t seconds after the fall is ​s(t)
Paul [167]

Answer: v= 160ft/s

a=32ft/s^2 constant

Explanation:

s(t)=400-16t^2 derivative of position is velocity v(t) and derivative of velocity is acceleration a(t) so let s(t)=0 to find the time of flight to reach the ground and take the two derivatives and use the time found and solve. Also acceleration is a constant as it’s gravity.

0=400-16t^2

400=16t^2

25=t^2

t=5s

ds/dt=v(t)=0-32t

dv/dt=a(t)=-32 constant(gravity)

v(t)=-32(5s)= -160ft/s negative sign is only showing direction

7 0
3 years ago
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