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schepotkina [342]
3 years ago
5

N2 + o2 -------> N2 O5

Chemistry
1 answer:
Wewaii [24]3 years ago
7 0
2 N2 + 5 O2 ----> 2N2O5 
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Precipitation can mean rain, snow or hail. In chemistry, precipitation is the formation of a _________ from _____________?
ratelena [41]

Answer:

percipitate or sedements from chemical reactions

8 0
3 years ago
Which is not true for a catalyst?
maria [59]

Answer: (A) It appears as a reactant in the net chemical reaction

Explanation:

A catalyst is  A substance that speed up the chemical reaction without its self being consumed in the reactants or the products.It does this by lowering the activation energy of the reaction by speeding up the rate of reaction.

3 0
3 years ago
SrCl2(aq)+2NaF(aq)⟶SrF2(s)+2NaCl(aq)
aleksandr82 [10.1K]

Answer:

  • 637.636 mL of NaF
  • 0.7014 moles of SrF2

Explanation:

C_{1}V_{1} = C_{2}V_{2}

Where 1 and 2 represent NaF and SrCl2 respectively; and C and V ae concentration and volume.

0.110 × V1 = 0.420 × 167

<em>V1 = </em>\frac{70.14}{0.110}<em> = 637.636 mL ≈ 0.638 L.</em>

Mole ratio of SrF2:

mole ratio of SrCl2 : SrF2 is 1 : 1 (also, conc × vol = no. of moles )

<em>∴ moles of SrF2 = 0.7014.</em>

4 0
3 years ago
What is the pH of a solution that has 7.8x10-9 [H+]?
xxTIMURxx [149]

Answer:

8.11

Explanation:

pH = -log[H+]

pH = -log[7.8 x 10^{-9}]

pH = 8.107905...

pH = 8.11

5 0
3 years ago
2. 14g of Nitrogen gas and 8.0g of hydrogen react to produce ammonia according to the equation: N2 + 3H2 -- 2NH3 Calculate the m
GREYUIT [131]

Based on the equation of the reaction, nitrogen is the limiting reagent while hydrogen is the excess reagent.

<h3>What is the mole ratio of hydrogen to nitrogen in the formation of ammonia?</h3>

Hydrogen and nitrogen combines to form ammonia ina mole ratio of 3 : 1 as shown by the equation of the reaction below:

  • N2 + 3H2 -- 2NH3

The number of moles of the reactants in 14g of Nitrogen gas and 8.0g of hydrogen is calculated as follows:

  • Moles = mass/molar mass

Molar mass of N_{2} = 14.0 g

Molar mass of H_{2} = 2.0 g

Moles of N_{2} = 14/14.0 = 1 mole

Moles of H_{2} = 8/2.0 = 4 moles

Based on the data above:

  • The limiting reagent is nitrogen gas as it will be used up while hydrogen will be left over.
  • The moles of nitrogen is 1 mole
  • Hydrogen is the excess reagent and 1 mole will be left over
  • 3 moles of hydrogen will react with 1 mole of the nitrogen gas
  • mass of 3 moles of hydrogen is 3 × 2.0 g = 6.0g

Therefore, the limiting reagent is nitrogen while hydrogen is the excess reagent.

Learn more about limiting reagent at: brainly.com/question/24945784

3 0
3 years ago
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