Question

A solid disk has a mass of 162 kg and a radius of 1.30m. This

Answer 1

Answer:

754.3 m

Explanation:

The moment of inertia of the solid disk:

$I = mR^2/2$

Where m is the disk mass and R is the radius of the disk.

$I = 162*1.3^2/2 = 136.89 kgm^2$

The angular kinetic energy of the disk is then:

$E_k = I\omega^2/2 = 136.89 * 18^2/2 = 22176.18 J$

By law of energy conservation, this energy is converted to potential energy to pick up the 3kg block

let g = 9.8 m/s2

$E_p = m_bgh = 22176.18 J$

where $m_b$ = 3 kg is the mass of block

$3*9.8h = 22176.18$

$h = \frac{22176.18}{3*9.8} = 754.3 m$