Answer:
The options are not provided, so i will answer in a general way.
We know that:
The movement is along a straight horizontal surface, then we have one-dimensional motion.
The speed is 2m/s
We want a graph of position vs time.
Now, remember the relation:
Distance = Speed*Time
Then we can write the position as a function of time as:
P(t) = 2m/s*t + P0
Where t is our variable, that represents time in seconds, and P0 is the position at time t = 0seconds, we can assume that this is zero.
Then the equation is:
P(t) = 2m/s*t
And the graph is something like:
To solve the problem it is necessary to identify the equation in the manner given above.
This equation corresponds to the displacement of a body under the principle of simple harmonic movement.
Where,

PART A) Our equation corresponds to

Therefore the value of omega is equivalent to that of

From the definition we know that the period as a function of angular velocity is equivalent to



This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the
Is equivalent to . So the maximum speed that the body can reach is,



Therefore the maximum felocity will be 5ft / s
PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then


Answer:
u = 25 m/s
Explanation:
given,
length of skid = 93 m
coefficient of friction = 0.35
final velocity = 0 m/s
initial velocity = ?
force here is friction f = μ mg
F = ma
now com paring
-μ mg = m a
a = - μ g
a = - 0.35 x 9.8
a = -3.43 m/s²
we know,
v² = u² + 2 a s
0 = u² - 2 x 3.43 x 93
u² = 637.98
u = 25.26 m/s
u = 25 m/s (two significant figure)
Answer:
Accuracy
Explanation:
Accuracy means making measurements that are close to the value precision means making measurement that are close in value to eachother but not necessarily close to the true value.
I hope this helps! If not sorry.
The total displacement of the toy car at the given positions is 0.
The given parameters;
- <em>First displacement of the car, = 5 cm left</em>
- <em>Second displacement of the car, = 8 cm right</em>
- <em>Third displacement of the car, = 3 cm to the left</em>
The total displacement of the car is calculated as follows;
- <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
- <em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

Thus, the total displacement of the toy car at the given positions is 0.
Learn more about displacement here: brainly.com/question/18158577