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Fynjy0 [20]
3 years ago
9

Sea Food is a rich source of ______. *​

Physics
2 answers:
k0ka [10]3 years ago
8 0

Answer:

Sea Food is a rich source of ______. *​

Explanation:

Seafood is a rich source of minerals, such as iron, zinc, iodine, magnesium, and potassium.

Alexandra [31]3 years ago
3 0

Answer:

Sea food is a rich source of protein

Explanation:

You should eat fish (if you are not vegan/ vegetarian ofc) at least 2 times a week and 1 has to be oily

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Their are fewer or more elements than compounds?
zimovet [89]

There are 92 elements that are found in nature.  Roughly 80 of those are capable of combining with each other to make compounds, so there are a lot more than 92 compounds.

Example:  Take carbon and hydrogen.  (please)

Carbon and hydrogen combine to make methane, ethane, propane, pentane, hexane, heptane, octane, butane, and several more 'tanes'.

And if you have some oxygen along with the carbon and hydrogen, you can
make all the alcohols there are, plus vinegar.

4 0
3 years ago
Read 2 more answers
A car has negative acceleration. What information can you infer from this? (4 points) a The car is speeding up and changing its
mario62 [17]

Answer:

D. The car is slowing down.

Explanation:

When a car slows down, the acceleration is in the opposite direction as the velocity. With that being said, the car would have negative acceleration.

hope this helps!! p.s. i really need brainliest :)

5 0
3 years ago
The addition of electron shells results in _____
vodka [1.7K]

Answer:

shielding of electrons

Explanation:

The addition of electrons shells results in the shielding of electrons away from the nucleus, most importantly the nuclear pull resulting from the charge.

  • The nucleus pulls electrons to itself due to the net positive charge on it.
  • As more electronic shell is added, the effect of the pull weakens outward.
  • The inner shell experiences the nuclear pull more than the outer shell electrons.

The effect is responsible for a wide range of properties of elements.

6 0
3 years ago
A rock band playing an outdoor concert produces sound at 120 dB 5.0 m away from their single working loudspeaker. What is the so
joja [24]

ANSWER:100dB

f<em>rom the  sound intensity level,the sound intensity is calculated as:</em>

<em />\beta<em>₁=</em>\beta<em>=(10dB)㏒₁₀(l₁/l₀)</em>

<em>inserting numbers:</em>

<em>120dB=(10dB)㏒₁₀[l₁/10⁻¹²W/m⁸] or 12=㏒₁₀[l₁/(10⁻¹²)W/m²</em>

<em>Getting the antilog of both sides and obtain 10¹²=l₁(10⁻¹²W/m²)which </em>

<em>can be used to solve for l₁ and get</em>

<em>          l₁=(10⁻¹²W/m²)(10¹²)=1 W/m²</em>

<em>since the sound  intensity is related to the power and that the power does not change,the sound intensity at any other point can be solved.Plugging-in</em>

<em>ᵃ = 4πr²,into P=l₁ₐ₁=l₂ₐ₂ and get:</em>

<em>l₂=l₁(r₁/r₂)² =(1W/m²)(5/35) =2.04×10⁻²W/m²</em>

<em>since we know the sound intensity at the sound point 2r,the sound intensity level at the point can be solved.We have:</em>

<em>     </em>\beta<em>₂=</em>\beta<em>=(10dB)㏒₁₀(l₂/l₀)=(10dB)㏒₁₀(2.04×10⁻²/1×10⁻²)</em>

<em>    </em>\beta<em>₂=(10dB)㏒₁₀(2.04×10¹⁰)</em>

<em />\beta<em> =(10dB)[㏒₁₀(2.04)+㏒₁₀(10¹⁰)]=10dB[0.32+10]=103dB=100dB</em>

<em />

3 0
3 years ago
A fox is 7 meters from the base of a tree that is 15 m tall. A nest of owls is at the top of the tree. One of the owlets tosses
mamaluj [8]
Refer to the diagram shown below.

In this analysis, wind resistance is ignored, and g = 9.8 m/s².

The meat falls with zero vertical velocity, therefore the time, t, before the meat hits the ground is
\frac{1}{2}*(9.8 \, \frac{m}{s^{2}})*(t \, s)^{2} = (15 \, m) \\ t= \sqrt{ \frac{15}{4.9} }= 1.75 \, s

If the fox catches the meat before it hits the ground, then the fox should travel a horizontal distance d in the same time that the meat travels a horizontal distance (7 -d).
The meat travels a distance of 
7 - d = (1.2 m/s)*(1.75 s) = 2.1 m
or
d = 4.9 m

Let v =  velocity of the fox when it catches the meat.
If the acceleration of the fox is a m/s², then
v = 1.75a
Also,
d= \frac{1}{2} *(a \,  \frac{m}{s^{2}} )*(1.75 \, s)^{2} =  \frac{1}{2}( \frac{v}{1.75})^{2}*(1.75^{2})  \\ 4.9 = 0.875v^{2} \\ v^{2} = 5.6 \\ v = 2.366 \, m/s

Answer:  2.37 m/s  (nearest hundredth)



5 0
3 years ago
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