Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
The roots of the equation are x =
and x = 
and there are no real roots of the equation given above
Step-by-step explanation:
To solve:
5x² − 3x + 17 = 9
or
⇒ 5x² − 3x + 17 - 9 = 0
or
⇒ 5x² − 3x + 8 = 0
Now,
the roots of the equation in the form ax² + bx + c = 0 is given as:
x = 
in the above given equation
a = 5
b = -3
c = 8
therefore,
x = 
or
x = 
or
x =
and x = 
or
x =
and x = 
here i = √(-1)
Hence,
The roots of the equation are x =
and x = 
and there are no real roots of the equation given above
Check the picture below.
A)
well, we start off by making a table of values for the function, with a few "t" values, as you see in the picture, then graph those points to get the graph.
B)
at t = 0, h(0) = 98, and at t = 1, h(1) = 82, so it went from 98 to 82, for a difference of 16.
C)
at t = 1, h(1) = 82, and at t = 2 h(2) = 34, so it went from 82 to 34, for a difference of 48.
does it fall the same distance on both intervals? well, they're different, so nope.
Answer: 122°
Step-by-step explanation:
When an angle is supplementary to each other , it means the angle measures to 180°.
Now since one of the two angles is 58°, therefore, the other angle will be
180° - 58°
= 122°