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Ostrovityanka [42]

3 years ago

12

As the mass of an object in uniform circular motion increases, what happens to the centripetal force required to keep it moving

at the same speed?

1 answer:

Dmitriy789 [7]3 years ago

7 0

Answer:

It increases, because the centripetal force is directly proportional to the mass of the rotating body.

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A 0.09-kg lead bullet traveling 182 m/s strikes an armor plate and comes to a stop. If all of the bullet's energy is converted t

Artemon [7]

Answer: Δθ = 127.4 K

Explanation: by using the law of conservation of energy, the kinetic energy of the bullet equals the heat energy on the plate.

Kinetic energy of bullet = mv²/2

Heat energy = mcΔθ

Where m = mass of bullet = 0.09kg, v = velocity of bullet = 182 m/s, c = specific heat capacity of lead bullet = 130 j/kgk

Δθ = change in temperature

mv²/2 = mcΔθ

With 'm' on both sides of the equation, they cancel out each other, hence we have that

v²/2 = cΔθ

v² = 2cΔθ

Δθ= v²/2c

Δθ = (182)²/2×130

Δθ = 33124/260

Δθ = 127.4 K

3 0

3 years ago

A spherical capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has a radi

Svetlanka [38]

Answer: a) 73.41 10^-12 F; b)4.83* 10^3 N/C; c) 3.66 *10^3 N/C

Explanation: To solve this problem we have to consider the following: The Capacity= Charge/Potential Difference

As we know the capacity is value that depend on the geometry of the capacitor, in our case two concentric spheres.

So Potential Difference between the spheres is given by:

ΔV=- $\int\limits^a_b {E} \, dx$

Where E = k*Q/ r^2

so we have $\int\limits^a_b {K+Q1/r} \, dr$

then

Vb-Va=k*Q(1/b-1/a)=kQ (ab/b-a)

Finally using C=Q/ΔV=ab/(k(b-a))

To caclulate the electric firld we first obtain the charge

Q=ΔV*C=120 V*73.41 10^-12 F=8.8 10^-9 C

so E=KQ/r^2 for both values of r

r=12.8 cm ( in meters)

r2=14.7 cm

E(r1)=4.83* 10^3 N/C

E(r2)=3.66 *10^3 N/C

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3 years ago

Are we actually touching nothing but electrons in reality or can we actually feel things without the electron barier?

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Objects in contact with each other never get past the electron clouds of the atoms on their surfaces.

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3 years ago

A 37 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block ar

Ne4ueva [31]

Answer:

The frictional force acting on the block is 14.8 N.

Explanation:

Given that,

Weight of block = 37 N

Coefficients of static = 0.8

Kinetic friction = 0.4

Tension = 24 N

We need to calculate the maximum friction force

Using formula of friction force

$f=\mu mg$

Put the value into the formula

$f=0.8\times37$

$f=29.6\ N$

So, the tension must exceeds 29.6 N for the block to move

We need to calculate the frictional force acting on the block

Using formula of frictional force

$f = \mu N$

Put the value in to the formula

$f=0.4\times37$

$f=14.8\ N$

Hence, The frictional force acting on the block is 14.8 N.

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3 years ago

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3 years ago