Speed = distance/time
= 400/72
=5.55 m/s
Option B makes best sense, correct me if i’m wrong
Answer:
68.8 Hz
137.6 Hz, 206.4 Hz
Explanation:
L = Length of tube = 2.5 m
v = Velocity of sound in air = 344 m/s
Distance between nodes is given by

Where n = 0, 1, 2, 3, ...
Making n+1 = n

where n = 1, 2, 3 .....
For fundamental frequency n = 1

Frequency is given by

The fundamental frequency is 68.8 Hz
First overtone

Second overtone

The overtones are 137.6 Hz, 206.4 Hz
Hey There!
Electrical metallic tubing would be used in an electrical installation because it <span>is less expensive.</span>