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sleet_krkn [62]
2 years ago
14

Is the mechanical form of power different from the electrical form? Why?

Physics
1 answer:
valentinak56 [21]2 years ago
4 0

The potential energy of the charges due to the voltage between the terminals is converted to kinetic energy in the device. These devices are called passive components or loads; they 'consume' electric power from the circuit, converting it to other forms of energy such as mechanical work, heat, light, etc.

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Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the p
PSYCHO15rus [73]

Answer:

Energy density will be 14.73 J/m^3

Explanation:

We have given capacitance C=225\mu F=225\times 10^{-6}F

Potential difference between the plates = 365 V

Plate separation d = 0.200 mm 0.2\times 10^{-3}m

We know that there is relation between electric field and potential

E=\frac{V}{d}, here E is electric field, V is potential and d is separation between the plates

So E=\frac{V}{d}=\frac{365}{0.2\times 10^{-3}}=1825000N/C

Energy density is given by E=\frac{1}{2}\varepsilon _0E^2=\frac{1}{2}\times 8.85\times 10^{-12}\times (1.825\times 10^6)^2=14.73J/m^3

5 0
2 years ago
Through which gas in the table will sound waves travel faster than they would
Leni [432]

Answer: Methane

Explanation: I just took the AP€X quiz and Methane was the correct answer!

4 0
3 years ago
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A stone tumbles into a mine shaft strikes bottom after falling for 4.2 seconds. How deep is the mine shaft
ziro4ka [17]
d = u \times t \: + \frac{1}{2} \times a \times {t}^{2}
Since initial velocity is zero hence , u = 0

=> d = 1/2 * a * t2

d = 0.5 \times 9.8 \times {4.2}^{2}
on solving we get

d = 86.436 metres


Note ; Here Gravitational Acceleration is take as , g = 9.8 m/s2
3 0
3 years ago
What does it mean for a chemical equation to be balanced?
kolezko [41]

Answer:

<h2>The number of each type of atom is the same for both the reactants and products.</h2>

I hope this helps

3 0
3 years ago
If an object is thrown in an upward direction from the top of a building 1.6 x 102 ft. high at an initial velocity of 21.82 mi/h
stiv31 [10]
In this case, the object is thrown upwards from the building. Therefore, it first achieves some height before its starts dropping.

Now, when going upwards
v^2 = u^2 - 2gs

Where,
v = final velocity
u = initial velocity
g = gravitational acceleration
s = height achieved from the top of he bulding

Using the values given;
v = 0 (comes into rest before it starts dropping)
u = 21.82 mi/h = 32 ft/s
g = 9.81 m/s^2 = 32.174 ft/s^2

Then,
0^2 = 32^2 - 2*32.174*s
32^2 = 2*32.174*s
s = (32^2)/(2*32.174) = 15.91 ft

After achieving that height, it starts to drop from rest to maximum velocity when it hits the ground.
Applying the same formula;
v^2 = u^2 + 2gs

Where;
v = velocity when it hits the ground
u = initial velocity, 0 ft/s as it starts from rest
s = 15.91+1.6*10^2 = 15.91+160 = 175.91 ft

Therefore,
v^2 = 0^2 + 2*32.174*175.91
v^2 = 11319.68
v = Sqrt (11319.68) = 106.39 ft/s ≈ 32.43 m/s moving downwards.
5 0
3 years ago
Read 2 more answers
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