Answer:
Q = 797.5 cal
Explanation:
Given that,
Mass of iron, m = 50 g
The temperature rises from 55°C to 200°C.
We need to find the heat needed to raise the temperature. The heat raised is given by :
Put all the values,
So, 797.5 calories of heat is needed.
Answer:
V = 1.84 × 10³ L
Explanation:
You need to use the Ideal Gas Law and solve for volume.
PV = nRT
V = nRT/P
First, you need to convert the pressure to atm.
1 atm = 760 mm Hg
948/760 = 1.247 atm
Next, convert grams of xenon to moles. The molar mass is 131.293 g/mol.
128/131.293 = 0.975 mol
You now have all of the values needed.
P = 1.247 atm
n = 0.975 mol
R = 8.314 J/mol*K
T = 283 K
Plug the values in and solve.
V = nRT/P
V = (0.975 × 8.314 × 283)/1.247
V = 1.84 × 10³ L
The volume of the sample will be 1.84 × 10³ L.
Answer:
Silver
Explanation:
Given parameters:
Mass = 116g
Energy = 511J
Initial temperature = 21.6°C
Final temperature = 40.5°C
Unknown:
Specific heat capacity and the type of metal = ?
Solution:
To solve this problem, we need to find the specific heat capacity of the metal given,
H = m x c x Ф
H is the energy
m is the mass
c is the specific heat capacity
Ф is the change in temperature
511 = 116 x c x (40.5 - 21.6)
511 = 2192.4c
c = 0.233J/g°C
The specific heat capacity of silver is similar to this.
Answer:
58.32
Explanation:
The mass number is one mole and for Mg it is 24.306 for O it is 15.999 and for H it is 1.008. because O and H have 2, you multiply them by 2 and add all the numbers and it equals 58.32
Answer:
A dono wat is da anser sori man hehe
