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Alla [95]
3 years ago
5

Fig. 6.1 shows the structural formula of an organic compound.

Chemistry
2 answers:
Tatiana [17]3 years ago
6 0

Answer:

A dono wat is da anser sori man hehe

Tasya [4]3 years ago
4 0

Answer:

(a).

→ Hydroxyl group.

→ Carbon-carbon double bond. ( alkene )

→ Esters.

(c).

(I). A colourless solution : with bromine atoms on cyclo hexene.

or: A white precipitate due to bromine atoms formed on phenol.

(ii). The purple solution turns colourless due to oxidation of the cyclo hexene.

(iii).

Bubbles of a colourless gas ( hydrogen gas ) formed when sodium reacts with the hydroxyl group to form Sodium oate ions.

(iv). Am not sure about my answer.

(v).

A red dye is formed. ( and azo dye is formed due to benzenediazonium salt reacting with phenol ).

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vova2212 [387]

Answer:

34 atoms

Explanation:

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3 years ago
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20 Points!!<br><br> Need it as soon as possible.
Solnce55 [7]

Answer:

D.

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The equations given in the problem introduction can be added together to give the following reaction: overall: N2O4→2NO2 However
Murljashka [212]

Answer:

Reverse the 2 NO_2 \longrightarrow 2 NO + O_2  reaction

Explanation:

Reactions:

2 NO_2 \longrightarrow 2 NO + O_2

N_2O_4 \longrightarrow 2 NO + O_2

Overall:

N_2O_4 \longrightarrow 2 NO_2

As can be seen, in the overall reaction we have N_2O_4 in the reactants like in the second reaction and NO_2 in the products. The NO_2 is in the first reaction but as a reactant so we need to reverse that reaction:

2 NO + O_2 \longrightarrow 2 NO_2

N_2O_4 \longrightarrow 2 NO + O_2

Combining:

N_2O_4 + 2 NO + O_2\longrightarrow 2 NO + O_2 + 2 NO_2

N_2O_4 \longrightarrow 2 NO_2

4 0
3 years ago
Which of the following shows how rate depends on concentrations of reactants?
Katarina [22]

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Rate = k(A)m(B)n

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A.P.E.X.

6 0
3 years ago
(( PLEASE HELP QUICK ))Which expression can be used to calculate the ratio of the rate of effusion of gas A to the rate of effus
borishaifa [10]

Answer:

The square root of the molar mass of B ÷ the square root of the molar mass of A  

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases A and B, the ratio of their rates of effusion is

\dfrac{r_{\text{A}}}{r_{\text{B}}} = \sqrt{\dfrac{M_{\text{B}}}{M_{\text{A}}}}

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