<h3>Answer:</h3>
7.57 × 10⁻²² g of F
<h3>Solution:</h3>
Data Given:
Number of Molecules = 8
M.Mass of BF₃ = 67.82 g.mol⁻¹
Mass of Fluorine atoms = ?
Step 1: Calculate Moles of BF₃
Moles = Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Putting value,
Moles = 8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Moles = 1.33 × 10⁻²³ mol
Step 2: Calculate Mass of BF₃:
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹
Mass = 9.0 × 10⁻²² g
Step 3: Calculate Mass of Fluorine Atoms:
As,
67.82 g BF₃ contains = 57 g of F
So,
9.0 × 10⁻²² g will contain = X g of F
Solving for X,
X = (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g
X = 7.57 × 10⁻²² g of F
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Explanation:
Answer:
Therefore the equilibrium number of vacancies per unit cubic meter =2.34×10²⁴ vacancies/ mole
Explanation:
The equilibrium number of of vacancies is denoted by
.
It is depends on
- total no. of atomic number(N)
- energy required for vacancy
- Boltzmann's constant (k)= 8.62×10⁻⁵ev K⁻¹
- temperature (T).

To find equilibrium number of of vacancies we have find N.

Here ρ= 8.45 g/cm³ =8.45 ×10⁶m³
= Avogadro Number = 6.023×10²³
= 63.5 g/mole

g/mole
Here
=0.9 ev/atom , T= 1000k
Therefore the equilibrium number of vacancies per unit cubic meter,

=2.34×10²⁴ vacancies/ mole
Answer:
Thermometer A, because it measures accurately to the tenths digit.