The enthalpy change for the reaction 2K + S + K2S using the following thermochemical reactions is mathematically given as
dn=70.7kg
<h3>What is the enthalpy change for the reaction?</h3>
Generally, the equation for the Chemical reaction is mathematically given as
2k+s----->K2S
Therefore
KS+K----->K2S
Therefore
dn=dn1+dn2
dn=32.5+38.2
dn=70.7kg
In conclusion, the enthalpy change is
dn=70.7kg
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Alpha particles; they can be blocked with a sheet of paper
Here, the three different notation of the p-orbital in different sub-level have to generate
The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number depends upon the value of l, which are -l to +l.
Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as , and in space.
The three p-orbital can be distinguish by the quantum numbers as-
For 2p orbitals (principal quantum number is 2)
1) n = 2, l = 1, m = -1
2) n = 2, l = 1, m = 0
3) n = 2, l = 1, m = +1
Thus the notation of different p-orbitals in the sub level are determined.
Its C..... A pegmatitic is a crystals usually larger than 2.5 cm in size.... look in to it? :)
Answer:
5g sucrose
Explanation:
The solution of 50mL can be assumed to the same density as water (1g/mL), and therefore a mass of 50g. A solution of 10% sucrose has 5g of sucrose:
(50g)(0.10) = 5g
In order to make the solution, 5g of sucrose should be added to about 40mL of water and dissolved completely. The solution may then be poured into a 50mL volumetric flask and diluted to the mark.