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Rina8888 [55]
3 years ago
12

You have a gas with a density of 4.8 grams per Liter and a molar mass of 75.3 grams per mole. How many liters of gas do you have

if n = 3.1?
Chemistry
1 answer:
Andre45 [30]3 years ago
7 0

d = √((x1 - x2)2 + (y1 - y2)2)  

( -2 , 5 )   ( 12 , -1 )    

  ↑    ↑         ↑     ↑      

 x1    y1        x2    y2  

d = √((-2 - 12)2 + (5 - (-1))2) = √((-14)2 + 62) = √(196 + 36) = √232 = 2√58 ≈ 15.23

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Which type of intermolecular or interatomic force does methylated spirits fall under?​
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Intermolecular forces in ch3oh include London dispersion forces, dipole dipole attraction, and hydrogen bonding. Methylated spirits, a common industrial solvent, are mostly made of ethyl alcohol. Because methanol denatures ethyl alcohol, commercial supply is exempt from the typical taxes and charges imposed on alcohol. A quantity of methyl alcohol or phenol is added to make it so that drinking it will make you go blind. Alcohols have the hydrogen bonding and van der Waals intermolecular forces of attraction.

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A sample of gas at 30 degrees celcius occuoies 2.5 L at 1.3 atm. What volume will the sample occupyif pressure changes to 2 atm
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3 0
3 years ago
Which process is endothermic?a)b)c)d)The evaporation of water from the skin.The burning of candle wax.The oxidation of iron in a
BlackZzzverrR [31]

Answer:

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Explanation:

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6 0
3 years ago
HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make
vazorg [7]

<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.

<u>Explanation:</u>

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

\Delta G=\Delta H-T\Delta S

Where,

\Delta G = change in Gibb's free energy

\Delta H = change in enthalpy

T = temperature

\Delta S = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and Delta S is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the \Delta H is also negative.

For a reaction to be spontaneous, \Delta G must be negative.

-ve=-ve-[T(-ve)]\\\\-ve=-ve+T

From above equations, it is visible that \Delta G will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

8 0
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