The mass of nitrogen gas that participated in the chemical reaction is 1.54g
HOW TO CALCULATE MASS OF AN ELEMENT:
- Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;
- mass (M) = molar mass (MM) × number of moles (n)
According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.
- The molecular mass of nitrogen gas (N2) = 14.01(2)
= 28.02g/mol
Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:
- Mass (g) = 0.0550 mol × 28.02 g/mol
Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g
Learn more: brainly.com/question/18269198
The complete chemical formula for the unknown compound is N2O3 where X = 2 which is the oxidation state of oxygen.
<h3>What is oxidation state?</h3>
Oxidation state is the number of electron which the compound is giving or taking from each other to form the bonds as the oxidation is hight oxidation is happening asn if the low then reduction is happening.
In the compound N2O3 the oxidation state of O is 2 and the oxidation stte of N is 3 written in the cross-cross manner in compound.
Therefore, N2O3 where X = 2 which is the oxidation state of oxygen is complete chemical formula for the unknown compound.
Learn more about oxidation state, here:
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Answer:
the percentage yield of Cu(NO3) 2 is 40%
Answer:
0.95L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 1L
T1 (initial temperature) = 315K
P1 (initial pressure) = 1.10 atm
T2 (final temperature) = stp = 273K
P2 (final pressure) = stp = 1atm
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:
P1V1/T1 = P2V2/T2
1.1 x 1/315 = 1 x V2/273
Cross multiply to express in linear form.
315 x V2 = 1.1 x 273
Divide both side by 315
V2 = (1.1 x 273) /315
V2 = 0.95L
Therefore, the final volume of the system if STP conditions are established is 0.95L