Answer:
(d) 3,7-dimethyl-4-nonyne.
Explanation:
Hello,
In this case, considering the attached picture on which you can see that the main chain has nine carbon atoms, one tripe bond at the fourth carbon and two methyl radicals at the third and seventh carbons respectively, by following the IUPAC rules, the name would be: (d) 3,7-dimethyl-4-nonyne since the chain must start at the side closest to the first triple bond due to its priority and subsequently considering the present radicals.
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Answer : The correct option is, (b) +0.799 V
Solution :
The values of standard reduction electrode potential of the cell are:
![E^0_{[H^{+}/H_2]}=+0.00V](https://tex.z-dn.net/?f=E%5E0_%7B%5BH%5E%7B%2B%7D%2FH_2%5D%7D%3D%2B0.00V)
![E^0_{[Ag^{+}/Ag]}=+0.799V](https://tex.z-dn.net/?f=E%5E0_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D%3D%2B0.799V)
From the cell representation we conclude that, the hydrogen (H) undergoes oxidation by loss of electrons and thus act as anode. Silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half reaction will be:
Reaction at anode (oxidation) : 
Reaction at cathode (reduction) : 
The balanced cell reaction will be,
Now we have to calculate the standard electrode potential of the cell.
![E^o_{cell}=E^o_{[Ag^{+}/Ag]}-E^o_{[H^{+}/H_2]}](https://tex.z-dn.net/?f=E%5Eo_%7Bcell%7D%3DE%5Eo_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D-E%5Eo_%7B%5BH%5E%7B%2B%7D%2FH_2%5D%7D)
Therefore, the standard cell potential will be +0.799 V
Answer:
on the right side two and on left side it is6 yes it is a balanced equation pls mark me as the brainliset hope it helps you
2 atome nitrogen , 1 is correct
The correct answer is that last one
