Answer:
The percentage yield is 78.2g
Explanation:
Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.
Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)
First we need to calculate the moles of propane
Moles of propane =
g.mol-1
= 0.971 moles
So, moles of CO2 from the moles of propane
1 mole of C3H8(g) = 3 moles of CO2(g)
So, 0.971 moles of C3H8(g) = ?
= 2.913 moles of CO2
So theoretical yield = 2.913 moles
44.0 g/mol
= 128.2 g
So, the actual mass of CO2 = percent yield
theoretical yield / 100 %
= 61.0 %
128.2 g / 100 %
= 78.2 g
the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g
The question is incomplete as it does not have the options which has been provided in the attachment.
Answer:
1. sudden decrease
2. Respiratory alkalosis
Explanation:
Hyperventilation is a condition caused by the excess removal of the CO₂ from the blood which leads to the decrease in the pCO₂ of the arteries.
This decrease can cause fainting and death of the individual due to the malfunctioning of the body parts, especially the brain.
The decrease in the CO₂ amount of the blood causes the formation of bicarbonate and H⁺ ions which leads to respiratory alkalosis.
Therefore the selected options are correct.
Answer:
It would change the charge of the atom.
Explanation:
Added electrons cause atoms to be negatively charged, lost electrons cause atoms to be positively charged.
Answer:
B) The amount of vitamin D gained in 1 day.
Explanation:
When you combine protons and neutrons in the electrical charge they combine to make electricity