Answer: 27 is A and 28 is C.
Explanation: I’ll explain 28 but not 27 because that’s just definitions.
In CuSO4 there is a Cu, an S, and 4 O molecules. Add them up you get 6.
Answer:
<h3>The answer is 1000 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of object = 50 mL
density = 20 g/mL
We have
mass = 20 × 50
We have the final answer as
<h3>1000 g</h3>
Hope this helps you
Answer:
Solid: calcium and potassium
Liquid: mercury and bromine
Gaseous: oxygen and fluorine
Explanation:
Matter exists in three different states namely: solid, gaseous and liquid. Elements that are found in nature are classified as matter. Since, these elements are grouped as matter, they can either be found as either solids, liquids or gases at normal temperature and pressure.
At normal temperature (20°C or 293K) and pressure (1 atm), the following elements are found to exists in the respective state of matter:
Solid: Calcium (Ca) and potassium (K)
Liquid: Mercury (Hg) and bromine (Br)
Gaseous: Oxygen (O) and fluorine (F)
Hello!
Given the density of mercury being 13.57 g/mL, and the mass of 52 kilograms, we need to find the volume.
To find the volume, we need to divide mass by density (V = m/d).
Notice that you are given 52 kilograms, but not grams. To convert kilograms to grams, you need to multiply it by 1000.
52 x 1000 = 52000 grams
With the correct measurements, we can find the volume.
V = 52000 grams / 13.56 grams/milliliter
V ≈ 3834.80826
Therefore, the volume of the mercury is about 3,834.81 mL.
Answer: The volume of sample at 400 K is 
Explanation:
Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
(At constant pressure and number of moles)
where,
= initial volume of gas = 
= final volume of gas = ?
= initial temperature of gas = 360 K
= final temperature of gas = 400 K
Putting in the values we get:
Thus volume of sample at 400 K is
