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Reika [66]
3 years ago
5

What is the pH of a solution when the [OH - ] = 1 x 10 -3

Chemistry
1 answer:
dsp733 years ago
8 0

Answer:

The pH is 11

Explanation:

Because pH + pOH = 14

and pOH = - log [OH⁻] = - log (1 x 10⁻³) = 3

we can now calculate pH by manipulating equation one above

pH = 14 - pOH = 14 - 3 = 11

Thus the pH of the solution is 11

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What is the connection between Oobleck and the mantle?
lapo4ka [179]

Answer:

Oobleck is a mixture of cornstarch & water, a substance that behaves like the Mantle.

Explanation:

3 0
2 years ago
A slice of cheese has a mass of 14 g and a volume of 11 cm3. What is the density of the cheese in units of g/cm3 and g/mL
cluponka [151]

Answer:

Density =1.27g/cm

Explanation:

Density is the mass per volume of a substance.

That is

Density = mass/volume

Given that mass = 14g

Volume  = 11cm³

Therefore

Density = 14/11 g/cm³

Density =1.27g/cm³

I hope this was helpful, please mark as brainliest

4 0
3 years ago
A mineral always contains certain ___
const2013 [10]
A mineral always contain certain elements in definite proportions
4 0
3 years ago
Read 2 more answers
Lead(ii) iodide was prepared by reacting 65.0 ml of 0.218 m pb(no3)2 with 80.0 ml of 0.265 m ki. If the actual yield of the reac
Olegator [25]

The balanced chemical equation for the reaction is as follows:

Pb(NO_{3})_{2}+2KI\rightarrow PbI_{2}+2KNO_{3}

From the molarity and volume of Pb(NO_{3})_{2} and KI, number of moles can be calculated as follows:

n=M\times V

For Pb(NO_{3})_{2} :

n=0.218 M\times 65\times 10^{-3}L=0.01417 mol

Similarly, for KI:

n=0.265 M\times 80\times 10^{-3}L=0.0212 mol

From the balanced chemical reaction, 1 mol of Pb(NO_{3})_{2} gives 1 mole of PbI_{2} thus, 0.01417 mol will give 0.01417 mol.

Molar mass of PbI_{2} is 461.01 g/mol, mass can be calculated as:

m=n\times M=0.01417 mol\times 461.01 g/mol=6.53 g

Similarly, 2 mol of KI gives 1 mole of PbI_{2} thus, 0.0212 mol will give \frac{0.0212}{2}=0.0106 mol of PbI_{2}.

Mass can be calculated as:

m=n\times M=0.0106 mol\times 461.01 g/mol=4.88 g

The amount of PbI_{2} obtained from KI is less than that from  Pb(NO_{3})_{2} thus, KI is limiting reactant and amount of PbI_{2} obtained from KI will be theoretical yield.

Actual yield is 3.26 g, % yield can be calculated as follows:

percentage yield=\frac{Actual yield}{theoretical yield}\times 100

Putting the values,

percentage yield=\frac{3.26 g}{4.88 g}\times 100=66.80%

Therefore, % yield will be 66.80%.

3 0
3 years ago
How many grams of 40% (w/w) NaOH solution should be added to 600 g of water to obtain
Butoxors [25]

Explanation:

One mole of NaOH weighs 40gm.

Now 2M solution of NaOH indicates 2 moles of NaOH in 1 litre of water.

So the above question can now be simplified as …if one litre of water contains 80gm(2 moles) of NaOH, then how many grams of NaOH would 250ml solution of the same contain?

Using unitary method,

1000ml corresponds to 80gm NaOH…

1000/4 ml(250ml) corresponds to 80/4 gm NaOH…

Therefore, for 250ml of 2M NaOH, 20 gm of NaOH needs to be added to water.

7 0
2 years ago
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