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Aneli [31]
3 years ago
8

Based on conductivity values, classify the compounds in each set of solutions as molecular, ionic, or acids. what is the level o

f dissociation (complete, varying, or none) of each set
Chemistry
1 answer:
DochEvi [55]3 years ago
8 0
Electrolytic conductivity is measure of ability of solution to conduct electricity. It is also as specific conductance. Electrolytic conductivity is different as compared to electrical conductivity. Electrolytic conductivity increase with temperature, while electrical conductivity decreases with increasing temperature. Further, electrolytic conductivity occurs because of presence of ions in solutions, while electrical conductivity occurs due to presence of valence electrons.

In current context, number of ions present in solutions depends on dissociation constant values. For molecules, which donot under dissociation in solvent, no electrolytic conductivity will be observed. Generally, ionic compounds undergo complete dissociation in solution, hence they will display maximum conductance. In case of acids, conductivity values will vary depends upon dissociation constant values. Weak acid are characterized by lower dissociation constant values, hence they have lower conductivity as compared to strong acids.  <span />
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How many moles are in 8.63 x 103 atoms of Li?
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<h3>Answer:</h3>

1.43 × 10⁻²⁰ mol Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

8.63 × 10³ atoms Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 8.63 \cdot 10^3 \ atoms \ Li(\frac{1 \ mol \ Li}{6.022 \cdot 10^{23} \ atoms \ Li})
  2. Multiply/Divide:                \displaystyle 1.43355 \cdot 10^{-20} \ moles \ Li

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li

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Explanation:

It is given that,

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The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3

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So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.  

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