Answer:
100 newtons, 20 newtons per second
Step-by-step explanation:
The two congruent base angles tell us that this is an isosceles triangle, meaning the triangle has two congruent sides. Therefore, we can set these two expressions equal to each other and solve from there.
15x + 7 = 23x - 17
7 = 8x - 17
8x = 24
x = 3
Side = 15(3) + 7 = 45 + 7 = 52
Hope this helps!
Answer:
65.7
Step-by-step explanation:
Given the population of West Algebra can be modeled by the equation
P = 30. 1.04^T
If T is the number of years since 2000 and P is the population in millions, in 2020, T = 2020 - 2000 = 20
Substitute T = 20 into the expression and get T
P = 30. 1.04^20
P = 30(2.1911)
P = 65.73
Hence the amount of people that will be there in 2020 is 65.7million people
Answer: (3, -1)
Step-by-step explanation:
y = |x-3|-1
When y=|x|, vertex is (0, 0).
Now, let's translate the graph so it becomes y = |x-3|-1.
|x| ==> |x-3| Translate the graph 3 units to the right
Vertex: (0+3, 0) ==> (3, 0)
|x-3| ==> |x-3|-1 Translate the graph 1 unit down
Vertex: (3, 0-1) ==> (3, -1)
Vertex: (3, -1)
firstly let's convert the mixed fraction to improper fraction, then hmmm let's see we have two denominators, 5 and 3, and their LCD will simply be 15, so we'll multiply both sides by that LCD to do away with the denominators, let's proceed,
![\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{z}{5}-4=\cfrac{7}{3}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{15}}{15\left( \cfrac{z}{5}-4 \right)=15\left( \cfrac{7}{3} \right)}\implies 3z-60=35 \\\\\\ 3z=95\implies z=\cfrac{95}{3}\implies z = 31\frac{2}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%203%2B1%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B7%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7Bz%7D%7B5%7D-4%3D%5Ccfrac%7B7%7D%7B3%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B15%7D%7D%7B15%5Cleft%28%20%5Ccfrac%7Bz%7D%7B5%7D-4%20%5Cright%29%3D15%5Cleft%28%20%5Ccfrac%7B7%7D%7B3%7D%20%5Cright%29%7D%5Cimplies%203z-60%3D35%20%5C%5C%5C%5C%5C%5C%203z%3D95%5Cimplies%20z%3D%5Ccfrac%7B95%7D%7B3%7D%5Cimplies%20z%20%3D%2031%5Cfrac%7B2%7D%7B3%7D)