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creativ13 [48]
3 years ago
15

A piece of wood is 12 feet long and a nail is 3 inches long. The piece of wood is how many times as long as the nail?

Mathematics
2 answers:
Softa [21]3 years ago
7 0
The piece of wood is 48 times as long as the nail (12 feet = 144 inches) because 3 goes into 144 48 times.
Stolb23 [73]3 years ago
6 0

Answer:

the answer is 48


Step-by-step explanation:


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Plot the following points and find the area of the figure: (3,5); (-1,5); (-1,-3); (3,-3)
Westkost [7]

Answer:

im sorry i cant help you without a picture

Step-by-step explanation:

5 0
3 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
(Angle/triangle problem 25points)<br> What is the value of X?
Serhud [2]

Answer:

x = 5

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles in the triangle and equate to 180, that is

10x - 4 + 8x + 3 + 91 = 180

18x + 90 = 180 ( subtract 90 from both sides )

18x = 90 ( divide both sides by 18 )

x = 5


3 0
3 years ago
Steve was training for a race, he ran 3/4 of a
wariber [46]

Answer:

0.28571 miles (keystrokes)

3 0
3 years ago
Read 2 more answers
What are the prime factors of 34725346753856734573457812356273452743654376547654783674337864537644?
NeTakaya

Answer:

3475347396

Step-by-step explanation:

yep

7 0
4 years ago
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