Solve the following problem when -2 is outside an absolute value equation: -2|-2r-4|=-12
2 answers:
-2|-2r-4|=-12
divide by -2
|-2r-4| = 6
we get a positive and negative solution
-2r-4 = 6 and -2r - 4 = -6
-add 4 to each side
-2r = 10 -2r = -2
divide by -2
r = -5 and r = 1
Answer r = -5 ,1
<u>Answer: </u>
r = 1 and r = -5
<u>Step-by-step explanation: </u>
We are given the following problem with an absolute value equation:
The only variable here is so we will make it the subject and solve for it.
Isolating the absolute value by dividing the constant -12 by -2 to get:
Setting the quantity inside the absolute value notation equal to a positive and a negative value on the other side of the equation:
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3(2v+5)=33
Simplify both sides of the equation
3(2v+5)=33
Distribute
(3)(2v)+(3)(5)=33
6v+15=33
Subtract 15 from both sides
6v+15-15=33-15
6v=18
Divide both sides by 6
6v/6=18/6
V= 3
I hope that's help !
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