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zysi [14]
3 years ago
10

The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's

acceleration ?
Physics
2 answers:
Westkost [7]3 years ago
8 0

Hello!

The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's acceleration ?

We have the following data:

V (final velocity) = 10 m/s

Vo (initial velocity) = 30 m/s

ΔV  (speed interval)  = V - Vo → ΔV  = 10 - 30 → ΔV  = - 20 m/s

ΔT (time interval) = 4.0 seconds

a (average acceleration) = ? (in m/s²)

Formula:

\boxed{a = \dfrac{\Delta{V}}{\Delta{T}}}

Solving:

a = \dfrac{\Delta{V}}{\Delta{T}}

a = \dfrac{-20\:\dfrac{m}{s}}{4.0\:s}

\boxed{\boxed{a = - 5\:\frac{m}{s^2}}}\:\:\:\:\:\:\bf\green{\checkmark}

________________________________

\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}

masha68 [24]3 years ago
3 0
Acceleration (magnitude anyway) = (change in speed) / (time for the change) .

Change in speed = (10 - 30) = -20 m/s

Time for the change = 4.0sec

Magnitude of acceleration = -20/4  =  <em>-5 m/s² </em>
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128.21 m

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The original length can be obtained as follow:

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