The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
Answer:
the answer i got was a=−8b+24/b
Step-by-step explanation:
hoped I helped:)
Answer:
43
Step-by-step explanation:
7*3+22
1) 18
2) 4
3) 27
4) 9
5) x=8
6) x=6
Answer:
(1, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 3
y = -3x + 6
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 3 = -3x + 6
- [Subtraction Property of Equality] Subtract 6 on both sides: -3 = -3x
- [Division Property of Equality] Divide -3 on both sides: 1 = x
- Rewrite/Rearrange: x = 1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3(1) + 6
- Multiply: y = -3 + 6
- Add: y = 3