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kirill115 [55]
3 years ago
12

As the frequency of the ac voltage across a capacitor approaches zero, the capacitive reactance of that capacitor:___________.

Physics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

B) approaches infinity

Explanation:

The capacitive reactance of an AC capacitor is given by;

X_C = \frac{1}{\omega C } = \frac{1}{2\pi f C}

Where;

C is the capacitance

f is the frequency of the ac voltage

X_C = \frac{1}{\omega C} = \frac{1}{2\pi f C} \\\\X_C = \frac{1}{2\pi f C} \\\\X_C = \frac{1}{2\pi (0) C} \\\\X_C = \frac{1}{0} \\\\X_C = \ infinity

Therefore, as the frequency of the ac voltage across a capacitor approaches zero, the capacitive reactance of that capacitor approaches infinity.

The correct option is (B) approaches infinity

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A spring with spring constant of 26 N/m is stretched 0.22 m from its equilibrium position. How much work must be done to stretch
Evgen [1.6K]

Answer:

1.503 J

Explanation:

Work done in stretching a spring = 1/2ke²

W = 1/2ke²........................... Equation 1

Where W = work done, k = spring constant, e = extension.

Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.

Substitute into equation 1

W = 1/2(26)(0.34²)

W = 13(0.1156)

W = 1.503 J.

Hence the work done to stretch it an additional 0.12 m = 1.503 J

8 0
3 years ago
A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is
Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration a_{c} is given by the following equation:  

a_{c}=\frac{V^{2}}{r} (1)

Where:  

a_{c}=17 m/s^{2} is the <u>centripetal acceleration</u>

V is the<u> tangential speed</u>

r=12 m is the <u>radius</u> of the circle

Isolating V from (1):

V=\sqrt{a_{c}r} (2)

V=\sqrt{(17 m/s^{2})(12 m)}

<u />

Finally:

V=14.28 m/s This is the girl's tangential speed

3 0
3 years ago
A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.
Nataliya [291]

To solve the exercise it is necessary to take into account the definition of speed as a function of distance and time, and the speed of air in the sound, as well

v=\frac{d}{t}

Where,

V= Velocity

d= distance

t = time

Re-arrange the equation to find the distance we have,

d=vt

Replacing with our values

d= (343)(3.7)

d= 1269.1m

It is understood that the sound comes and goes across the entire lake therefore, the length of the lake is half the distance found, that is

L_{lake} = \frac{d}{2}

L_{lake} = \frac{1269.1}{2}

L_{lake} = 634.55m

Therefore the length of the lake is 634,55m

8 0
4 years ago
If a man walks 600 meters in 300 seconds, what was his speed in meters per second?​
kifflom [539]

Answer:

His speed in meters per second was 2. Or, 2 meters per second.

Explanation:

6 0
3 years ago
A flashlight has a resistance of 30 Q and is connected
Talja [164]

Answer:

3 A

Explanation:

The relationship between voltage, current and resistance in a conductor is expressed by Ohm's law, which states that:

V=RI

where:

V is the potential difference across the conductor

R is the resistance of the conductor

I is the current flowing through it

In this problem, for this flashlight we have:

V = 90 V is the potential difference

R=30 \Omega is the resistance of the flashlight

Solving for I, we find the current:

I=\frac{V}{R}=\frac{90}{30}=3 A

7 0
3 years ago
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