Question

A spring that is stretched 23 cm from its equilibrium point experiences a force of 103 N.a.) How much energy is stored in the spring?

Answer 1

Answer:

U = 11.85 J

Explanation:

given,

spring is stretched = 23 cm

                             x = 0.23 m

Force experiences = 103 N

we know,

 F = k x

where k is the spring constant

 $k =\dfrac{F}{x}$

 $k =\dfrac{103}{0.23}$

       k = 447.83 N/m

energy stored in the spring

 $U =\dfrac{1}{2}kx^2$

 $U =\dfrac{1}{2}\times 447.83 \times 0.23^2$

        U = 11.85 J

hence, energy stored in the spring is equal to U = 11.85 J