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mylen [45]
3 years ago
12

A 2.5g copper penny is given a charge of -4.0*10^-9c. how mny excess electrons are on the penny?

Physics
1 answer:
Lyrx [107]3 years ago
7 0

Answer : The excess of electrons on the penny are, 2.5\times 10^{10} electrons

Solution : Given,

Total charge = -4.0\times 10^{-9}C

Charge on electron = -1.6\times 10^{-19}C

Formula used :

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}

Now put all the given values in this formula, we get the excess of electrons present on the penny.

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}=\frac{-4.0\times 10^{-9}C}{-1.6\times 10^{-19}C/e^-}=2.5\times 10^{10}e^-

Therefore, the excess of electrons on the penny are, 2.5\times 10^{10} electrons


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The value is  B =  3.33 *10^{-6} \  T

Explanation:

From the question we are told that

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Generally the magnitude of the field exerted between the current carrying wire is

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Here B_1 is the magnetic field due to the first wire which is mathematically represented as

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Here d_1 is the distance to the half way point of the separation and the value is  

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B_2 is the magnetic field due to the first wire which is mathematically represented as

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Here d_2 is the distance to the half way point of the separation and the value is  

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Answer:

The concentration of hydrogen ion at pH is equal to 2 := [H^+]=0.01 mol/L

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Explanation:

The pH of the solution is the negative logarithm of hydrogen ion concentration in an aqueous solution.

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