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slamgirl [31]
3 years ago
13

The amount of gravitational pull between two bodies depends on their masses and which other variable? A. The speed they travel B

. Distance the bodies C. Size of their orbits around the sun D. Shape of the bodies
Physics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

The answer is  B. Distance the bodies

Explanation:

According to Newton's theory of gravitation, the gravitational interaction between two bodies can be expressed by a force directly proportional to the product of the masses of the bodies and inversely proportional to the square of the distance that separates them, this means that the force of attraction can be calculated taking the mass of the bodies and the distance that separates them.

It is expressed with the following formula:

F = G\frac{m1m2}{r^{2} } where (F) is force (G) is universal gravitational constant (m1) is mass of the body1 (m2) is mass of the body2 and (r) is the distance between the bodies.

Mrrafil [7]3 years ago
3 0
 A because speed is a major factor

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How will frost on the wings of an airplane affect takeoff performance?
san4es73 [151]

Frost will disturb the smooth flow of air over the wing, unpleasantly distressing its lifting competence. In other words, this spoils the even flow of air over the wings, by this means decreasing lifting capability. Also, frost may avoid the airplane from becoming flying at normal departure speed.

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3 years ago
Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s
kkurt [141]

Answer:

B. Steam burns the skin worse than hot water because the latent heat of vaporization is released as well.

Explanation:

It is given that both steam and the boiling water when in contact with the skin cools down from 100 to 34 degrees Celsius.

For any substance of mass m, the heat required to change the temperature by \Delta T is mC\Delta T (S.I. unit = Joules).

where C, the specific heat capacity is the same and a constant for both the condensed steam and the boiling water.  

But, there is a "hidden" energy (heat) released by the steam called latent heat

(given by mL, L = specific latent heat) which allows the phase transition (gas to liquid). While both of them are at the same temperature, their energy (heat) is different, which is why steam causes burns worse than boiling water

3 0
3 years ago
Why can't we implement the center tapped full wave rectifier without center-tapped transformer
maksim [4K]
For a full wave bridge you don't want a center tap
6 0
3 years ago
In a circus act, a 70 kg clown is shot from a cannon with an initial velocity of 17 m/s at some unknown angle above the horizont
EleoNora [17]

Answer:

K_{2}=7302.4J

Explanation:

Given the initial velocity of the clown, his mass and final height we can calculate the final kinetic energy using the <em><u>conservation of total mechanical energy</u></em>

K_{1}+U_{1}=K_{2}+U_{2}

K_{2}=K_{1}+U_{1}-U_{2}

K_{2}=\frac{1}{2}mv_{1}^{2}+mgh_{1}-mgh_{2}

Since h_{1}=0

K_{2}=\frac{1}{2}mv_{1}^{2}-mgh_{2}

K_{2}=\frac{1}{2}(70kg)(17m/s)^2-(70kg)(9.8m/s^2)(4.1m)=7302.4J

K_{2}=7302.4J

7 0
3 years ago
What tension would you need to make a middle c (261.6 hz) fundamental mode on a 1 m string (for example, on a harp)? the linear
Allisa [31]
The frequency of middle C on a string is
f = 261.6 Hz.

The given linear density is
ρ = 0.02 g/cm = (0.02 x 10⁻³ kg)/(10⁻² m)
   = 0.002 kg/m

The length of the string is L = 1 m.

Let T =  the tension in the string (N).
The velocity of the standing wave is
v= \sqrt{ \frac{T}{\rho} }

In the fundamental mode, the wavelength, λ, is equal to the length, L.
That is
Because v = fλ, therefore
\sqrt{ \frac{T}{\rho} } =f \lambda = fL \\\\ \frac{T}{\rho} = (fL)^{2} \\\\ T = \rho (fL)^{2}

From given information, obtain
T = (0.002 kg/m)*(261.6 1/s)²*(1 m)²
   = 136.87 N

Answer: 136.9 N (nearest tenth)

4 0
3 years ago
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