1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
UNO [17]
3 years ago
13

2. A 1.30-m long gas column that is open at one end and closed at the other end has a fundamental resonant frequency 80.0 Hz. Wh

at is the speed of sound in this gas?
Physics
1 answer:
Elina [12.6K]3 years ago
7 0

To solve this problem, it will be necessary to apply the concepts related to the fundamental resonance frequency in a closed organ pipe.

This is mathematically given as

f_n (2n+1)(\frac{v}{4L})

For fundamental frequency n is 0, then,

f_0 = \frac{v}{4L}

When,

v = Velocity of sound

L = Length,

Rearranging to find the velocity,

v = f_0 (4L)

v = (80Hz)(4)(1.3m)

v = 416m/s

Therefore the speed of sound in this gas is 416m/s

You might be interested in
The energy of a photon is proportional to its a) amplitude. d) wave number, k-2m/A c) velocity. b) frequency
Scilla [17]

Answer:

Frequency

Explanation:

Photons are the packet of energy. They are massless and chargeless particles. They travel in the vacuum with the speed of light. The energy of photon is given by :

E=h\nu

Where

h = Planck's constant

\nu = frequency of photon

Or E=\dfrac{hc}{\lambda}

c = speed of light

\lambda = wavelength of photon

From the above equation, it is clear that the energy of photon is directly proportional to its frequency.

5 0
3 years ago
Help plzzz itz importannnttt
krok68 [10]

Answer:

➢ ➢ ➢ ✔3. How did Nazis treat their enemies?✔3. How did Nazis treat their enemies?

4 0
2 years ago
Read 2 more answers
A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance fr
NARA [144]
To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.

Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds

Horizontal distance
=0.335s*1.2m/s
=0.402 meters
8 0
3 years ago
What is the mass, in kg, of a 136 pound gymnast on Earth?
Rzqust [24]

Answer:

61.6886 kg

Explanation:

6 0
2 years ago
Plz help me
Reil [10]

Answer:

Yes

Explanation:

When an object has more mass it takes more gravity to keep it down therefore producing friction which in return reduces the amount of kinetic energy created. A change in an object's speed has an greater effect on its kinetic energy. than a change in its mass has, because kinetic energy is proportional to.

3 0
3 years ago
Other questions:
  • People who have color vision deficiency typically lack one or more of the three cones that are sensitive to a particular wavelen
    7·2 answers
  • 2. If it takes Ashley 3 seconds to run from the batter’s box to first base at an average speed of 6.5 meters per second, what is
    15·2 answers
  • When voltage increases and resistance remains constant what must happen to current? A) Current must decrease. B) Current must in
    15·2 answers
  • A uniform bar of length 3.7 m and mass 4.5 kg is attached to a wall through a hinge mechanism which allows it to rotate freely.
    14·1 answer
  • What is the key point from the kennedy-nixon debate​
    5·1 answer
  • The amount of energy absorbed by a vehicle in an impact is related to __________ A. the direction of the impact. B. the design o
    11·2 answers
  • A physics student has a battery and three equal resistors. If she uses all of the
    8·2 answers
  • What is the mass of a vehicle that has 50,000 N and 25M/S/S
    9·1 answer
  • A power plant burns coal to generate electricity. Suppose that 1000 J of heat (Q) from the coal fire enters a boiler, which is k
    7·1 answer
  • What is the strength of the intermolecular forces between liquid and gas <br>​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!