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UNO [17]
4 years ago
13

2. A 1.30-m long gas column that is open at one end and closed at the other end has a fundamental resonant frequency 80.0 Hz. Wh

at is the speed of sound in this gas?
Physics
1 answer:
Elina [12.6K]4 years ago
7 0

To solve this problem, it will be necessary to apply the concepts related to the fundamental resonance frequency in a closed organ pipe.

This is mathematically given as

f_n (2n+1)(\frac{v}{4L})

For fundamental frequency n is 0, then,

f_0 = \frac{v}{4L}

When,

v = Velocity of sound

L = Length,

Rearranging to find the velocity,

v = f_0 (4L)

v = (80Hz)(4)(1.3m)

v = 416m/s

Therefore the speed of sound in this gas is 416m/s

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Answer:

Image result for In covalent bonds what is being shared

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

Explanation:

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2 years ago
Free Brainliest. Who is faster, Sonic or the car from back to the future?
viva [34]

Answer:

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Explanation:

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3 years ago
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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
laila [671]

Answer:

1.45544 J

Explanation:

See attachment

5 0
3 years ago
At the race track, one race car starts its engine with a resulting intensity level of 104.0 dB at point P. Then 6 more cars star
dem82 [27]

To solve the problem it is necessary to apply the concepts related to sound intensity. The most common approach to sound intensity measurement is to use the decibel scale:

\beta (dB) = 10log_{10}(\frac{I}{I_0})

Where,

I_0 = 1*10^{-12} is a reference intensity. It is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz.

I = Sound intensity

Our values are given by,

\beta = 104dB

\#Autos = 7

For each auto the intensity would be,

104 = 10log\frac{I}{1*10^{-12}}

10.4= log_{10} (\frac{I}{10^{-12}})

10^{10.4}*10^{-12}=I

I = 0.02511W/m^2

Therefore the sound intesity for the 7 autos is

I= 7* 0.02511

I = 0.1748W/m^2

The sound level for the 7 cars in dB is

\beta (dB) = 10log_{10}(\frac{0.1748}{1*10^{-12}})

\beta (dB) = 112.42dB

8 0
3 years ago
Big Ben, a large artifact in England, has a mass of 1x10^8 kilograms and the Empire State Building 1x10^9 kilograms. The distanc
TiliK225 [7]

Answer:

The force, exerted by Big Ben on the Empire State Building is 2.66972 × 10⁻⁷ N

Explanation:

The question relates to the force of gravity experienced between two bodies

The given parameters are;

The mass of Big Ben, M₁ = 1 × 10⁸ kg

The mass of the Empire State Building, M₂ = 1 × 10⁹ kg

The distance between the two Big Ben and the Empire State Building, r = 5,000,000 meters

By Newton's Law of gravitation, we have;

F=G \times \dfrac{M_{1} \times M_{2}}{r^{2}}

Where;

F = The force exerted by Big Ben on the Empire State Building and vice versa

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

M₁, M₂, and r are the given parameters

By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;

F=6.67430 \times 10^{-11} \times \dfrac{1 \times 10^8 \times 1 \times 10^9}{(5,000,000)^{2}} = 2.66972 \times 10^{-7}

The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.

3 0
3 years ago
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