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UNO [17]
3 years ago
13

2. A 1.30-m long gas column that is open at one end and closed at the other end has a fundamental resonant frequency 80.0 Hz. Wh

at is the speed of sound in this gas?
Physics
1 answer:
Elina [12.6K]3 years ago
7 0

To solve this problem, it will be necessary to apply the concepts related to the fundamental resonance frequency in a closed organ pipe.

This is mathematically given as

f_n (2n+1)(\frac{v}{4L})

For fundamental frequency n is 0, then,

f_0 = \frac{v}{4L}

When,

v = Velocity of sound

L = Length,

Rearranging to find the velocity,

v = f_0 (4L)

v = (80Hz)(4)(1.3m)

v = 416m/s

Therefore the speed of sound in this gas is 416m/s

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In a discussion person A is talking 1.2 dB louder than person B, and person C is talking 3.2 dB louder than person A. What is th
liberstina [14]

Answer: 3.84dB

Explanation:

Since person A is talking 1.2dB louder than B, we will have

A = 1.2B... (1)

Similarly, person C is talking 3.2 dB louder than person A, we have

C = 3.2A... (2)

From equation 1, B = A/1.2... (3)

To get the ratio of the sound intensity of person C to the sound intensity of person B, we will divide equation 2 by 3 to give

C/B = 3.2A/{A/1.2}

C/B = 3.2A×1.2/A

C/B = 3.2×1.2

C/B = 3.84dB

3 0
3 years ago
What can you observe to know that when clear methane gas is burned it is a chemical change?
aalyn [17]
<span>4) Formation of a gas

When methane burns, it produces the gases water vapor and carbon dioxide.
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6 0
3 years ago
An object is placed 5.00 cm beyond the focal point of a convex lens whose focal length is 10.0 cm. If the object height is 3.0 c
Aleks04 [339]

Answer:

The height of the image is, h' = 6.0 cm

The image is erect.

Explanation:

Given data,

The object distance, u = -5 cm

The focal length of convex lens, f = 10 cm

The object height, h = 3 cm

The lens formula,

                      \frac{1}{f}=\frac{1}{v}-\frac{1}{u}

                      \frac{1}{10}=\frac{1}{v}-\frac{1}{-5}

                      \frac{1}{v}=\frac{1}{10}-\frac{1}{5}

                      v = -10 cm

The magnification factor of lens

                     m=\frac{-10}{-5}

                     m = 2

                     m=\frac{h'}{h}

                     h'=h\times m

                     h'=3\times 2

                     h' = 6 cm

The height of the image is, h' = 6 cm

The image is erect.

4 0
3 years ago
He power output of a cyclist moving at a constant speed of 5.3 m/s on a level road is 120 w. (a) what is the force exerted on th
EleoNora [17]
P=F*V
F=P/V
F=120/5.3
F=22.6N

8 0
3 years ago
An artificial satellite is moving in a circular orbit of radius 24,600 km. Calculate its speed if it takes 12hours to revolve ar
denis-greek [22]

Answer:

the speed of the satellite is 12,880.53 km/h

Explanation:

Given;

radius of the circular orbit, r = 24,600 km

time taken to revolve around Earth, t = 12 hours

The circumference of the satellite is calculated as;

L = 2πr

L = 2π x 24,600 km

L = 49,200π km

L = 154,566.36 km

The speed of the satellite;

v = L/t

v = 154,566.36 / 12

v = 12,880.53 km/h

Therefore, the speed of the satellite is 12,880.53 km/h

6 0
3 years ago
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