Answer:
She can swing 1.0 m high.
Explanation:
Hi there!
The mechanical energy of Jane (ME) can be calculated by adding her gravitational potential (PE) plus her kinetic energy (KE).
The kinetic energy is calculated as follows:
KE = 1/2 · m · v²
And the potential energy:
PE = m · g · h
Where:
m = mass of Jane.
v = velocity.
g = acceleration due to gravity (9.8 m/s²).
h = height.
Then:
ME = KE + PE
Initially, Jane is running on the surface on which we assume that the gravitational potential energy of Jane is zero (the height is zero). Then:
ME = KE + PE (PE = 0)
ME = KE
ME = 1/2 · m · (4.5 m/s)²
ME = m · 10.125 m²/s²
When Jane reaches the maximum height, its velocity is zero (all the kinetic energy was converted into potential energy). Then, the mechanical energy will be:
ME = KE + PE (KE = 0)
ME = PE
ME = m · 9.8 m/s² · h
Then, equallizing both expressions of ME and solving for h:
m · 10.125 m²/s² = m · 9.8 m/s² · h
10.125 m²/s² / 9.8 m/s² = h
h = 1.0 m
She can swing 1.0 m high (if we neglect dissipative forces such as air resistance).
The word gravity is used to describe the gravitational pull (force) an object experiences on or near the surface of a planet or moon. The gravitational force is a force that attracts objects with mass towards each other. Any object with mass exerts a gravitational force on any other object with mass.
Hope it answers your question!
Brainliest would be nice but of course you don’t gotta :)
It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8).
This question is incomplete, the complete question is;
The electric force due to a uniform external electric field causes a torque of magnitude 20.0 × 10⁻⁹ N⋅m on an electric dipole oriented at 30° from the direction of the external field. The dipole moment of the dipole is 7.5 × 10⁻¹² C⋅m.
What is the magnitude of the external electric field?
If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle?
Answer:
- the magnitude of the external electric field is 5333.3 N/C
- the magnitude of the charge on each particle is 3.0 × 10⁻¹² C ≈ 3 nC
Explanation:
Given that;
Torque = 20.0 × 10⁻⁹ N⋅m
dipole moment = 7.5 × 10⁻¹²
∅ = 30°
The moment T of restoring couple is;
T = PEsin∅
E = T/Psin∅
we substitute
E = 20.0 × 10⁻⁹ N⋅m / (7.5 × 10⁻¹²) sin(30°)
E = 20.0 × 10⁻⁹ / 3.75 × 10⁻¹²
E = 5333.3 N/C
Therefore, the magnitude of the external electric field is 5333.3 N/C
The dipole moment is given by the expression;
p = ql
q = p / l
given that l = 2.5 mm = 0.0025 m
we substitute
q = 7.5 × 10⁻¹² / 0.0025
q = 3.0 × 10⁻¹² C ≈ 3 nC
Therefore, the magnitude of the charge on each particle is 3.0 × 10⁻¹² C ≈ 3 nC
