Answer
Integral EdA = Q/εo =C*Vc(t)/εo = 3.5e-12*21/εo = 4.74 V∙m <----- A)
Vc(t) = 21(1-e^-t/RC) because an uncharged capacitor is modeled as a short.
ic(t) = (21/120)e^-t/RC -----> ic(0) = 21/120 = 0.175A <----- B)
Q(0.5ns) = CVc(0.5ns) = 2e-12*21*(1-e^-t/RC) = 30.7pC
30.7pC/εo = 3.47 V∙m <----- C)
ic(0.5ns) = 29.7ma <----- D)
Answer:
-3044.848m/s^2
Explanation:
Initial velocity = 15.7 m/s (u)
Final velocity = -14.444 m/s (v) velocity after striking moving opposite direction.
Time = 0.0099 s
Average acceleration :
change in velocity/ total time
= V - U/t
= -14.444 m/s - 15.7 m/s/0.0099 s
= -30.144/0.0099 s
= -3044.848m/s^2
