PWR stands for many things. Since you're talking about nuclear power reactors I think PWR stands for pressurized water reactor.
A pressurized water reactor follows many steps but the main goal is to obtain thermal energy from water.
Hope it helped,
BioTeacher101
Answer:
A. Up
B. Out
C. Out
D. To equilibrum
Explanation:
a. The reaction in an exothermic reaction so this means heat is given off. If the cylinder is thin enough heat will transfer to the water bath
b. Since the products will create heat which will increase pressure, the piston in an attempt to maintaining a constant pressure will move up to accommodate building pressure.
c. Heat will flow out of the gaseous mixture as this reaction creates heat as a product as well
d. Heat will flow out in the capacity to create an equilibrium with the water bath that it is in.
Answer:
4.16x10⁻³m
Explanation:
Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.
As there are 100g of solvent, <em>the kg are 0.1. </em>Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.
<em>Moles glucose:</em>
There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.
Molar mass glucose:
6C = 12.01g/mol*6 = 72.06g/mol
12H = 12*1.008g/mol = 12.10g/mol
6O = 6*16g/mol = 96g/mol
72.06 + 12.10 + 96 = 180.16g/mol
Moles of 0.075g of glucose:
0.075g * (1 mol / 180.16g) =
4.16x10⁻⁴ moles of glucose
<em>Molality of the solution:</em>
4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =
<h3>4.16x10⁻³m</h3>
Answer:
Only white phosphorus is stored under water. White phosphorus spontaneously reacts with oxygen in the air to burst into flame to form phosphorus pentoxide
Explanation:
We have to first find the number of moles of Freon-12 in the sample using the ideal gas law equation
PV = nRT
n =

since the number of moles at both conditions given and at stp we can write the following formula

where parameters for the given conditions are on the left side and parameters for STP conditions are on the right side of the equation
where P1 - pressure - 252.5 kPa
V1 - volume - 28.42 x 10⁻³ m³
R - universal gas constant
T1 - 331 K
STP conditions
P2 - 101 325 Pa
T2 - 273 K
substituting these values in the equation

V = 58.41 L
Volume at STP is 58.41 L