If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they
1 answer:
Answer:
Step-by-step explanation:
The master chief has three and a half cookies i.e. numbers of cookies.
Again the arbiter has five and three quarters of a cookie i.e. number of cookies.
Therefore, in total there are numbers of cookies.
If we divide the total number of cookies in to equal parts and distribute to then then each of them will get numbers of cookies. (Answer)
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Answer:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
Explanation:
1) Given two side lenghts and one angle you can use sine law:
2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:
From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:
From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
Explanation:
1) Given two side lenghts and one angle you can use sine law:
2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:
From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:
From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°