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DaniilM [7]
3 years ago
11

If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they

have in total? How many cookies would each get if the sum of cookies was split between them?SERIOUS QUETION! (My teacher is into halo, so yeah.)
Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

9\dfrac{1}{4}

4\dfrac{5}{8}

Step-by-step explanation:

The master chief has three and a half cookies i.e. 3\dfrac{1}{2} = \dfrac{7}{2} numbers of cookies.

Again the arbiter has five and three quarters of a cookie i.e. 5\dfrac{3}{4} = \dfrac{23}{4} number of cookies.

Therefore, in total there are (\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4} numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get \dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8} numbers of cookies. (Answer)  

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Answer:

A: -11

B: Two complex solutions

Step-by-step explanation:

The discriminant of this equation is 3^2-20=9-20=-11. Since the discriminant is negative, its square root will be an imaginary number, and there will be two complex solutions. Hope this helps!

3 0
3 years ago
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butalik [34]

The geometric sequence is starting with 2 and multiplying by 3 every time. We can get the rule of this sequence by...

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6 0
3 years ago
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6 0
2 years ago
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Answer:

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