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7nadin3 [17]
3 years ago
7

The fundamental frequency of a string fixed at both ends is 316 hz. how long does it take for a wave to travel the length of thi

s string?
Physics
1 answer:
lina2011 [118]3 years ago
8 0

yfzufsfusgsuzguugzdigidggddyi

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When potential energy is converted into Kinetic energy, some of that kinetic energy is always in the form of
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Explanation: Thermal energy is the conversion of kinetic energy

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Please help me with this very easy question I just don’t get it.
diamong [38]

Answer:

150m

Explanation:

The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).

So we need to compute the integral of speed over time from 0.0s to 5.0s.

The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).

The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2

distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m

Alternatively, we can use the acceleration formula:

a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2

distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.

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2 years ago
If launched at the right speed, what could eventually happen to objects launched from Newton's theoretical cannon on the top of
Nadusha1986 [10]
If the speed is higher than the orbital velocity, but not high enough to leave Earth altogether (lower than the escape velocity), it will continue revolving around Earth along an elliptical orbit. (D) for example horizontal speed of 7,300 to approximately 10,000 m/s for Earth.
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2 years ago
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Kruka [31]
<h3>You forgot to add question...Add questions before asking so we can help</h3>
4 0
2 years ago
Read 2 more answers
- Una carga de -5x10-6 C está situada a 20cm delante de otra
saul85 [17]

Answer:

F = 5.625\,N (Fuerza de repulsión/Repulsive force)

Explanation:

La fuerza ejercida entre las dos partículas se calcula por la Ley de Coulomb (The force exerted between the two particles is determined by Coulomb's Law):

F = k \cdot \frac{q_{1}\cdot q_{2}}{r^{2}}

Donde (Where):

k - Constante electrostática, medido en \frac{N\cdot m^{2}}{C^{2}} (Electrostatic constant, measured in \frac{N\cdot m^{2}}{C^{2}}).

q_{1}, q_{2} - Magnitudes de las cargas de cada partícula, medidos en Coulombs. (Magnitudes of charges from each particle, measured in Coulombs).

r - Distancia entre las partículas, medida en metros.

La fuerza electrostática es (Electrostatic force is):

F = \left(9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot \frac{(5\times 10^{-6}\,C)\cdot (5\times 10^{-6}\,C)}{(0.20\,m)^{2}}

F = 5.625\,N

Dado que las partículas tienen el mismo signo de carga, la fuerza es de repulsión. (Given that both particles have the same charge sign, the force is of repulsive nature)

3 0
2 years ago
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