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vodomira [7]
3 years ago
10

In Speed Study Number 1, we looked at two cars traveling the same distance at different speeds on city streets. Car "A" traveled

at a speed of 35 miles per hour. Car "B" traveled at 45 miles per hour. Both cars traveled a distance of 10 miles. How much sooner did Car "B" arrive at its destination than Car "A"?
Physics
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

230.4 s

Explanation:

The speed of car A is

v_A = 35 mi/h

and the distance travelled is

d = 10 mi

so the time taken for car A is

t_A = \frac{d}{v_A}=\frac{10 mi}{35 mi/h}=0.286 h

The speed of car B is

v_B = 45 mi/h

and the distance travelled is

d = 10 mi

so the time taken for car B is

t_B = \frac{d}{v_B}=\frac{10 mi}{45 mi/h}=0.222 h

So the difference in time is

\Delta t = t_A - t_B = 0.286 h -0.222 h=0.064 h

Which corresponds to

\Delta t = 0.064 h \cdot 3600 s/h = 230.4 s

so car B arrived 230.4 s before car A.

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A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

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3 years ago
In a uranium fission reaction, uranium splits into two smaller atoms and energy. Where did the energy come from?
postnew [5]

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Explanation:

From Einstein's mass-energy relation:

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When Uranium atoms under go nuclear fission, smaller atoms are formed and huge amount of energy is released. This energy comes from the mass difference of the uranium nuclei and new nuclei formed. This mass converted into energy according to Einstein's equation.

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This question deals with the volume of different shapes.

a) volume of the sphere is "33.51 m³".

b) volume of the cylinder is "25.13 m³".

a)

The volume of a sphere is given by the following formula:

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<u>Volume = 33.51 m³</u>

<u />

b)

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